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4 years ago

5

Why does one side of the moon always face away from the earth?

1 answer:

Vladimir [108]4 years ago

5 0

only one side of the Moon is visible from Earth because the Moon rotates on its axis at the same rate that the Moon orbits the Earth :)

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Which of the following types of pollution is NOT linked to coal-burning power plant emissions?

Vika [28.1K]

A is not linked. Coal burning is not an effect of acid rain.
~Deceptiøn

8 0

3 years ago

Why does a bowling ball and a father fall at the same speed while in a vacuum? <br> PLZ NEED HELP

k0ka [10]

Answer:

there is no drag in a vacuum (why is father in a vaccum)

Explanation:

there is nothing to hit and slow the object other than gravity like dust or air

6 0

3 years ago

At what speed, as a fraction of c, does a moving clock tick at four fifth the rate of an identical clock at rest?

ololo11 [35]

Answer:

The seed as a fraction of the speed of light is $\frac{3}{5}c$

Solution:

As per the question:

Suppose, $t_{i}$ be the rate of an identical clock between two time intervals.

For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:

t = $\frac{5}{4}t_{i}$

Now,

Using the relation of time dilation, from Einstein's relation:

$t = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

$\frac{5}{4}t_{i} = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

Squaring both sides:

$(\frac{5}{4})^{2} = (\frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}})^{2}$

$\frac{25}{16} = \frac{1}{{1 - \frac{v^{2}}{c^{2}}}}$

$1 - \frac{16}{25} = \frac{v^{2}}{c^{2}}$

$\frac{v}{c} = \sqrt{\frac{9}{25}}$

$\frac{v}{c} = \frac{3}{5}$

$v = \frac{3}{5}c$

6 0

3 years ago

A vector in the xy plane has components -14.0 units in the x-direction and 30.0 units in the y-direction. What is the magnitude

OverLord2011 [107]

$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

We would calculate the magnitude by applying pythagorean theorem:

$\longrightarrow \sf{Magnitude= \sqrt{(-14)^2 } + 30^2}$

$\longrightarrow \sf{Magnitude = 33.12}$

$\longrightarrow \sf{The \: vector \: is \: (- 14, 30)}$

The angle between two vectors is given by the formula:

$\sf{\longrightarrow \small \cos \emptyset = \dfrac{(a1b1 + a2b2)}{ \sqrt{(a1)^2 + (a2)^2√(b1)^2 + (b2)^2} } }$

In two dimensional, the x axis of vector form is:

$\small\sf{\longrightarrow (b1, b2) = (1, 0) }$

$\sf{\longrightarrow \small \cos \: \emptyset = \dfrac{(14 * 1 + 30 x 0)}{( \sqrt{(-14)^2 + (30)^2)(√(1)^2 + (0)^2)} } }$

$\small\longrightarrow \sf{ \dfrac{14}{33.12} }$

$\small\longrightarrow \sf{\emptyset \: = arcCos (\dfrac{ - 14}{33.12} )}$

$\small\longrightarrow \sf{\emptyset= 115^\circ}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\small\bm{The \: angle \: between \: the \: vector \: }$

$\small\bm{and \: \: the \: \: positive \: \: x \: \: axis \: \: is \: \: \: 115^\circ .}$

6 0

2 years ago

HURRY!!! How does a sound wave travel through air?

Sergio039 [100]

Answer is B

Hope this helped!

8 0

3 years ago