3 years ago

In a lab, the mass of object A is 2.5 kg. Object A weighs:

Physics

1 answer:

dangina [55]3 years ago

8 0

Answer:

25N

Explanation:

Assuming the lab is on earth:

w = mg = 2.5 (9.81) = 25N

You might be interested in

Which term defines the energy of motion?

Korvikt [17]

D kinetic energy✨
nnnnnnnnnnnnbbbhhbbbbbbb

4 0

3 years ago

A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc

ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

$T=2\pi \sqrt{\frac{L}{g} }$

Where T is period

L is length of rod

g is acceleration due to gravity = $9.8m/s^{2}$

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this $L_{O}$

$L_{O} = 3/4 * 5.95m$

= 4.4625m

thus $T=2\pi \sqrt{\frac{L_{O} }{g} }$

$T=2\pi \sqrt{\frac{4.4625 }{9.8} }$

T= 4.24sec

8 0

3 years ago

Cells a and f shows an early and late stage of the same phase of mitosis . what phase is it?

Lerok [7]

Fun fhjzsh going chichi. Gok

3 0

4 years ago

A rocket-launching vehicle is moving forward at a constant velocity of 5 m/s. a cannon on the vehicle shoots a shell straight up

Readme [11.4K]

For any object thrown upwards where only the force of gravity is acting upon it, uses the following formula for the maximum height attained.

H= v²/2g, where g = 9.81 m/s²

There are two information of velocities are given. However, we use the 20 m/s information because this is the launch velocity. Hence, the solution is as follows:

H = (20 m/s)²/2(9.81 m/s²)
<em>H = 20.4 m</em>

5 0

3 years ago

Playing tetherball, a boy hits the 0.45 kg ball, moving toward him initially at 4.6 m/s, in the opposite direction at 2.5 m/s. H

saul85 [17]

Answer:

Explanation:

8 0

3 years ago