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olya-2409 [2.1K]
3 years ago
11

Because of barriers and obstructions you can see only a tiny fraction of a standing wave on a string. You do not know, for insta

nce, how long the string is. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. Can you determine the frequency of the standing wave?
1. Sure, the frequency is 500 Hz.
2. No, you have no way to know the number
of nodes, for instance.
3. Sure, the frequency is 10 Hz.
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Sure, the frequency is 500Hz

Explanation:

Sure, the frequency can be calculated. The needed information which is the speed and wavelength of the wave are known.

Wavelength is the distance between two successive crest and trough of a wave.

Using the relationship

V = fλ

V is the speed of wave

F is the frequency

λ is the wavelength

f = v/λ

Given v = 100m/s, λ = 10cm/0.5 = 20cm

20cm = 0.2m

f = 100/0.2

f = 500Hertz

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Answer:

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Explanation:

Given that :

mass of the block   m =  200.0 g  = 200 × 10⁻³ kg

the horizontal spring constant   k  =  4500.0 N/m

position of the block (distance x) = 4.00 cm  = 0.04 m

To determine the speed the block will be traveling when it leaves the spring; we applying the  work done on the spring as it is stretched (or compressed) with the kinetic energy.

i.e \frac{1}{2} kx^2  = \frac{1}{2} mv^2

kx^2 = mv^2

4500* 0.04^2 = 200*10^{-3} *v^2

7.2 =200*10^{-3}*v^{2}

v^{2}   =\frac{7.2}{200*10^{-3}}

v   =\sqrt{\frac{7.2}{200*10^{-3}}}

v = 6 m/s

Hence,the speed the block will be traveling when it leaves the spring is  6 m/s

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