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olya-2409 [2.1K]
3 years ago
11

Because of barriers and obstructions you can see only a tiny fraction of a standing wave on a string. You do not know, for insta

nce, how long the string is. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. Can you determine the frequency of the standing wave?
1. Sure, the frequency is 500 Hz.
2. No, you have no way to know the number
of nodes, for instance.
3. Sure, the frequency is 10 Hz.
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Sure, the frequency is 500Hz

Explanation:

Sure, the frequency can be calculated. The needed information which is the speed and wavelength of the wave are known.

Wavelength is the distance between two successive crest and trough of a wave.

Using the relationship

V = fλ

V is the speed of wave

F is the frequency

λ is the wavelength

f = v/λ

Given v = 100m/s, λ = 10cm/0.5 = 20cm

20cm = 0.2m

f = 100/0.2

f = 500Hertz

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3 years ago
a log splitter puts out 1 100W of power for every 1500 W put into it. the efficiency of the machine is what
hram777 [196]

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Explanation:

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I need help with these questions :<br>(see image )​
dem82 [27]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>

Height of Aeroplane = 500 meters

Speed of Aeroplane = 200 m/s

Acceleration due to gravity = g = 10m/s^2

time of package to reach the ground = t = ?

Horizontal distance = d = ?

<h2>_____________________________________</h2><h3>SOLUTION:</h3>

When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the plane as the plane is just moving in horizontal direction. So the bomb fall and will travel forward.

Initial horizontal velocity is given by,

                                            V_{ix} = 200 ms{-1}

Initial vertical velocity is given by,

                                            V_{iy} = 0m/s

By the second equation of motion under gravity,

                                           H = V_{iy}t + \frac{1}{2}gt^2\\\\500 = (0)t + \frac{1}{2}x10xt^2 \\\\500 = 0 + 5t^2\\\\t^2 = \frac{500}{5}\\\\t^2 = 100\\\\t = 10 seconds

<h2>_____________________________________</h2>

<u>For horizontal distance(d)</u>:

Horizontal distance has no acceleration thus d is given by

                                          d = vt

                                          d = 200x10

                                          d = 2000 meters

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

                 

4 0
3 years ago
A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have
Juliette [100K]

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

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A motorcyclists starts from rest and reaches a speed of 6m/s after traveling with uniform acceleration for 3s .What is his accel
siniylev [52]
2m/s is the answer ! hopefully this helps
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