1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olya-2409 [2.1K]
3 years ago
11

Because of barriers and obstructions you can see only a tiny fraction of a standing wave on a string. You do not know, for insta

nce, how long the string is. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. All you know is that the speed of waves on the string is 100 m/s and that the distance ? in the sketch is 10 cm. Can you determine the frequency of the standing wave?
1. Sure, the frequency is 500 Hz.
2. No, you have no way to know the number
of nodes, for instance.
3. Sure, the frequency is 10 Hz.
Physics
1 answer:
REY [17]3 years ago
7 0

Answer:

Sure, the frequency is 500Hz

Explanation:

Sure, the frequency can be calculated. The needed information which is the speed and wavelength of the wave are known.

Wavelength is the distance between two successive crest and trough of a wave.

Using the relationship

V = fλ

V is the speed of wave

F is the frequency

λ is the wavelength

f = v/λ

Given v = 100m/s, λ = 10cm/0.5 = 20cm

20cm = 0.2m

f = 100/0.2

f = 500Hertz

You might be interested in
Explain, step by step, how to calculate the amount of current (I) that will go through the resistor in this circuit
anygoal [31]

Answer:

0.03 A

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

From ohm's law, the voltage, current and resistor are related by the following formula:

Voltage = current × resistor

V = IR

With the above formula, we can obtain the current in the circuit as follow:

Voltage (V) = 12 V

Resistor (R) = 470 Ω

Current (I) =?

V = IR

12 = I × 470

Divide both side by 470

I = 12 / 470

I = 0.03 A

Thus, the current in the circuit is 0.03 A

3 0
2 years ago
Read 2 more answers
An arrow in flight has an initial velocity of 65 meters per second, and 10 seconds later, it has a velocity of 35 meters per sec
-BARSIC- [3]
Acceleration = (final velocity - initial velocity) / time
= (35-65)/10
= -3 m/s2
7 0
3 years ago
What is 12 and 1 half % expressed as a fraction
kiruha [24]
12 1/2 i would assume
6 0
3 years ago
Read 2 more answers
Ntally Check for Understanding
Wewaii [24]

Answer: 34

Explanation:

34

3 0
3 years ago
Hey can yall help me out in dis
Karolina [17]

Answer:

Scientific method

Explanation:

5 0
3 years ago
Other questions:
  • a field hockey ball is launched from the ground at an angle to the horizontal. what are the ball's horizontal and vertical accel
    11·1 answer
  • When heating water, during what temperature range will the temperature cease to change for some time?
    14·2 answers
  • The discovery that the universe appears to be expanding led to a widely accepted theory called ____?
    8·2 answers
  • What is the resultant of 5N force pointing north and 7N force pointing south? Do not forget include direction
    10·1 answer
  • What happens to the air resistance on a car as it speeds up? A) decreases b)stays the same C)it changes direction of the car D)i
    7·1 answer
  • The velocity of a particle is given by v=20t² - 100t + 50, where v is in meters per second and t is in seconds. Evaluate the vel
    13·2 answers
  • If a dog ran at 5 m/s how far would it run in 45 s
    15·2 answers
  • How do you choices of physical activities and food affect your fitness levels and health goals?
    11·1 answer
  • During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds.How many meters per second did the sprint increase with this amou
    15·1 answer
  • Which of the following, if eliminated, would completely prevent the greenhouse effect from occurring on earth?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!