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blagie [28]
4 years ago
7

A net force of magnitude 36 N gives an object of mass m1 an acceleration of 6.0 m/s^2. The same net force gives m1 and another o

bject of mass m2 fastened together an acceleration of 2.0 m/s^2. What acceleration will m2 experience if the same net force acts on it alone?
Physics
1 answer:
Jet001 [13]4 years ago
3 0
This is a beautiful problem to test whether a student actually understands
Newton's 2nd law of motion . . . Force = (mass) x (acceleration). 

That simple law is all you need to solve this problem, but you need to
use it a few times.

m₁ alone:
                     Force = (mass) x (acceleration)

                       36 N = ( m₁ ) x  (6 m/s²)

                         m₁ = (36 N) / (6 m/s²)   

                         m₁  =  6 kilograms .

m₁ and m₂ glued together:
                     Force = (mass) x (acceleration)

                       36 N = (6 kg + m₂) x (2 m/s²)

                     6 kg + m₂  =  (36 N) / (2 m/s²)  =  18 kilograms

                               m₂  =  12 kilograms .

m₂ alone:
                     Force = (mass) x (acceleration)

                       36 N = (12 kg) x (acceleration)

                     Acceleration = (36 N) / (12 kg)

                     Acceleration  =   3 m/s²


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Volgvan

Answer:

Weight on Venus = 443.75 N

Explanation:

Weight of a body is the product of mass and acceleration due to gravity.

So we have

       Weight =  Mass x Acceleration due to gravity

        W = mg

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        Acceleration due to gravity, g = 8.875 m/s²

        W = 50 x 8.875 = 443.75 N

Weight on Venus = 443.75 N

3 0
3 years ago
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A sled of mass m is given a kick on a frozen pond. The kick imparts to the sled an initial speed of 2.00 m/s . The coefficient o
kobusy [5.1K]

2.04 meters distance is traveled by the sled before stopping.

Mass of the sled = m

The initial speed of the sled = 2 m/s

Coefficient of kinetic friction between sled and ice = 0.100

Let the distance the sled moves before it stops be d.

Gravity = 9.8 m/ s²

Let the initial kinetic energy sled be

= K _{i}

K_{i} =  \frac{1}{2} mv ^{2}

The work done by the frictional force is,

Work \: done \:  by \: frictional \: force =W_{f}

W _{f} = μ_{k}mgd

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So, the distance traveled by the sled before stopping is

d= \frac{1mv ^{2} }{2 \:μ_{k}mg}

d= \frac{1v ^{2} }{2 \:μ_{k}g}

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Therefore, the distance traveled by the sled before stopping is 2.04 meters.

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5 0
2 years ago
Henry mixed salt and water together in a cup until he observed a clear solution. He measured the mass of the solution. Then he p
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Answer:

B- He is correct. Evaporation is a physical change, but dissolving salt in water is a chemical change. The change in mass is evidence that a chemical change occurred.

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6 0
3 years ago
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Q.01 When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False
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True, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.

<h3>Relationship between dielectric material and electric field</h3>

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Answer:

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It's almost hard and seismic waves move through the asthenosphere at a slow rate. The fragile lithosphere and the uppermost portion of the asthenosphere are assumed to be rigid.

seismic waves travel more quickly through denser materials and therefore generally travel more quickly with the depth it moves more slowly through a liquid than a solid. Molten areas within the Earth slow down P waves and stop S waves because their shearing motion cannot be transmitted through a liquid. Partially molten areas may slow down the P waves and attenuate or weaken S waves.

hope this helps...

5 0
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