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Zielflug [23.3K]
2 years ago
6

True or False: if the product of three numbers is negative, then all the numbers are negative?

Mathematics
1 answer:
S_A_V [24]2 years ago
3 0
This question would be false
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wants the perimeter of his rectangular garden to be, at most, 60 feet. He plans on making the length 19 feet. what is the maximu
Elina [12.6K]

Answer:

width = 11 feet

Step-by-step explanation:

The perimeter of a rectangle is 2 times length + width.

He already decided that the perimeter is at most 60 feet and the length is 19 feet. Then replacing in the formula for perimeter you have:

60 = 2 ( 19 + width)

30 = 19 + width

11 = width

Therefore the maximum width is 11 feet

3 0
3 years ago
Subtract -2x^2+4x-1−2x
vivado [14]

Answer:

8x²- x -8

Step-by-step explanation:

The question is not well written. I guess what you mean is:

Subtract -2x^2+4x-1 ( minus 2x squared plus 4x minus 1) from 6x^2+3x-9 (6x squared plus 3x minus 9).

To  subtract -2x^2+4x-1 from 6x^2+3x-9, that is

6x^2+3x-9 - (-2x^2+4x-1). This can be written as

6x²+3x-9 - (-2x²+4x-1)

Now, opening the bracket, we will get

6x²+3x-9 +2x²-4x+1

Then, collecting like terms, we get

6x²+2x²+3x-4x-9+1

6x²+2x² = 8x²

3x-4x = -x

-9+1 = -8

∴6x²+2x²+3x-4x-9+1 becomes

8x²-x -8

The answer is 8x²-x -8.

7 0
3 years ago
Geometry PEOPLE HELP
White raven [17]

Answer: second option.

Step-by-step explanation:

Given the transformation T:(x,y)→(x-5,y+3)

 You must substitute the x-coordinate of the point A (which is x=2) and the y-coordinate of the point A (which is y=-1) into (x-5,y+3) to find the x-coordinate and the y-coordinate of the image of the point A.

Therefore, you get that the image of A(2,-1) is the following:

(x-5,y+3)=(2-5,-1+3)=(-3,2)

You can observe that this matches with the second option.

6 0
3 years ago
On Monday, 375 students went on a trip to the zoo. All 9 buses were filled and 6 students had to travel in cars. how many stu
lozanna [386]

Answer:

41

Step-by-step explanation:

(375-6)÷9=369÷9=41

3 0
3 years ago
Read 2 more answers
At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul
vampirchik [111]

Answer:

a) Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b) The 95% confidence interval would be given by (910.05;959.95)    

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: \mu =900

Alternative hypothesis: \mu \neq 900

b. What is the 95% confidence interval estimate of the population mean examination  score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=935 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=180 represent the population standard deviation

n=200 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=3278.222

The sample deviation calculated s=97.054

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

935-1.96\frac{180}{\sqrt{200}}=910.05    

935+1.96\frac{180}{\sqrt{200}}=959.95    

So on this case the 95% confidence interval would be given by (910.05;959.95)    

c. Use the confidence interval to conduct a hypothesis test. Using α= .05, what is your  conclusion?

Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d. What is the p-value?

The statistic is given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

If we replace we got:

z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750

Since is a bilateral test the p value is given by:

p_v =2*P(Z>2.750)=0.0059

So then since the p value is less than the significance we can reject the null hypothesis at 5% of significance.

8 0
3 years ago
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