Answer : The freezing point of a solution is 
Explanation : Given,
Molal-freezing-point-depression constant 
= 
Mass of urea (solute) = 29.82 g
Mass of solvent = 500 g = 0.500 kg
Molar mass of urea = 60.06 g/mole
Formula used :
where,
= change in freezing point
= freezing point of solution = ?
= freezing point of solvent = 
i = Van't Hoff factor = 1 (for urea non-electrolyte)
= freezing point constant =
m = molality
Now put all the given values in this formula, we get
Therefore, the freezing point of a solution is
What are u asking there is no specific question
Answer:
Nicotinamide adenine dinucleotide
Flavin adenine dinucleotide
Explanation:
hope this helps ^^
Answer:
237.5 K.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.
</em>
where, P is the pressure of the gas in atm (P = 5.2 atm).
V is the volume of the gas in L (V = 15.0 L).
n is the no. of moles of the gas in mol (n = 4.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = ??? K).
∴ T = PV/nR = (5.2 atm)(15.0 L)/(4.0 mol)(0.0821 L.atm/mol.K) = 237.5 K.
