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puteri [66]
3 years ago
7

Is oxygen more reactive than beryllium

Chemistry
2 answers:
laiz [17]3 years ago
8 0

Answer:

Yes oxygen is more reactive than beryllium

gladu [14]3 years ago
6 0

Elemental beryllium is very unreactive towards air and water, even at high temperatures.

You might be interested in
which atoms are moving faster those in a spoon at 0 degrees fahrenheit or those in a fork 0 degrees celsius
myrzilka [38]
I would say the atoms in the fork are moving faster. 0 degrees Fahrenheit is -17.7778 in Celsius while 0 degrees in Celsius is equal to 32 degrees in Fahrenheit.
4 0
3 years ago
At what celsius temperature does 0.750mol of an ideal gas occupy a volume of 35.9L at 114kPa
pashok25 [27]

Answer:

378.25°C

Explanation:

Given data:

Number of moles of gas = 0.750 mol

Volume of gas = 35.9 L

Pressure of gas = 114 KPa (114/101 = 1.125 atm)

Temperature of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

now we will put the values.

T = PV/nR

T = 1.125 atm × 35.9 L /0.750 mol  × 0.0821 atm.L/ mol.K

T = 40.3875/0.062/K

T = 651.4 K

Kelvin to °C:

651.4 K - 273.15 = 378.25°C

8 0
4 years ago
a stone is found to have a volume of 34.9cm3. it has a mass of 30.8g. what is the density of the stone
FromTheMoon [43]

Answer:

Explanation:

ρ =  

m

V

=  

30.8 gram

34.9 cubic meter

=  0.88252148997135 gram/cubic meter

=  0.00088252148997135 kilogram/cubic meter

3 0
4 years ago
Drag each label to the correct location on the image.
kap26 [50]

Answer:

1.Products

2.Reactants

3.Activation

4.Chemical potential energy

5.Energy

6.Activated

7.Complex

8.Progress of reaction

9.Enthalpy of Reaction

7 0
3 years ago
Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t
nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

n = \frac{m}{M}

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol

The enthalpy change is:

\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0
3 years ago
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