Answer:
483.27 minutes
Explanation:
using second faradays law of electrolysis
Just divide the two (2 / 0.05) and you will get your answer; there are 40 drops of bloodin the collection tube.
I think the above conversion is an example of A.) ALPHA DECAY.
In Alpha decay, nucleus releases an alpha particle, Helium. When the alpha particle is released the remaining nucleus weighs less due to the decrease in neutrons and protons have also decreased in number.
Answer:
Mass ratio of magnesium = 2 : 1
Explanation:
Let us write down the masses of element involve to form the compounds .
Compound A → 7.88 g of mg and 15.68 g of 02
Compound B → 2.12 g of mg and 6.91 g of 02
since we want to get the mass ratio of magnesium, we divide the mass of mg with the other element present (oxygen) . we want to make both compound in equal proportions.
Compound A → 7.88 / 15.68 = 0.5025510204 g of Mg
/1 g of Oxygen
Compound B → 2.12 / 6.91 = 0.30680173661 g of Mg/ 1 g of Oxygen
Mass ratio of magnesium = compound A(Mg)/compound B(Mg)
Mass ratio of magnesium = 0.5025510204/0.30680173661
Mass ratio of magnesium = 1.63803186368
/1
Mass ratio of magnesium = 2 : 1
Answer:
Removing O₂, means removing one of the reactants and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.
Explanation:
The principle that explains how changes in temperature, Concentration and Pressure of reactants or products of a reaction at equilibrium affect the equilibrium position of the reaction is the Le Chatelier's principle.
The Principle explains that a system/process if a system/process which is at equilibrium is disturbed/perturbed/constrained by one or more changes (in concentration, pressure or temperature), the system would shift the equilibrium position to counteract the effects of this change.
Removing O₂, means removing one of the reactants (changing its concentration) and the system would counteract this effect by producing more O₂, thereby shifting the equilibrium position to the left and favouring the backward reaction.