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lozanna [386]
3 years ago
14

Find the area of a rectangle with length (x- 3) and width (x + 5).

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

x^2+2x-15

Step-by-step explanation:

A=L*W

A=(x-3)(x+5)

A=x^2+5x-3x-15

A=x^2+2x-15

hope this helps ya!

can i get brainliest please?

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Escribe una ecuación de la recta que pasa por el punto (5, –8) con pendiente 5.
Nana76 [90]

Considerando la expresión de una ecuación lineal, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

<h3>Ecuación lineal</h3>

Una ecuación lineal o línea se puede expresar en la forma y = mx + b

donde

  • x y son coordenadas de un punto.
  • m es la pendiente.
  • b es la ordenada al origen y representa la coordenada del punto donde la línea cruza el eje y.

La ecuación lineal se puede expresar también mediante la ecuación punto-pendiente de la recta, que se plantea si se conoce la pendiente de la recta y cualquiera de sus puntos. Con ello queda determinada la recta, conociendo la pendiente  “m” y un punto  (x1, y1) dado:

y - y1= m(x -x1)

<h3>Ecuación de la recta en este caso</h3>

En este caso, la recta que pasa por el punto (5, –8) con pendiente 5.

Reemplazando en la ecuación punto-pendiente de la recta:

y - (-8)= 5(x -5)

Resolviendo:

y + 8= 5(x -5)

Aplicando propiedad distributiva:

y + 8= 5x - 5×5

y + 8= 5x - 25

Aislando la variable "y":

y= 5x - 25 - 8

<u><em>y= 5x - 33</em></u>

Finalmente, la ecuación de la recta que pasa por el punto (5, –8) con pendiente 5 es y= 5x - 33.

Aprende más sobre ecuación de una recta:

brainly.com/question/25243069

brainly.com/question/19260315

brainly.com/question/24766917

#SPJ1

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Which algebraic expression represents one-fifth of x less than 6.2?
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