Answer:
1.428 moles
Explanation:
If 0.0714 moles of N2 gas occupies 1.25 L space,
how many moles of N2 have a volume of 25.0 L?
Assume temperature and pressure stayed constant.
we experience it 0.0714 moles: 1.25L space
x moles : 25L of space
to get the x moles, cross multiply
(0.0714 x 25)/1.25
1.785/1.25 = 1.428 moles
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10.49
3MgO + 2Fe — Fe2O3 + 3Mg
n(Fe2O3) = m/M
=15/159.69
=0.9393199324mol
1 Mol of Fe2O3 = 2 moles of Fe
Therefore n(Fe) =2 * 0.9393199324
=0.1878639865mol
m(Fe) = n*m.m
= 0.1878639865 * 55.8
=10.4828g