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Tatiana [17]
2 years ago
10

Who is wise president of india?________________________​

Chemistry
1 answer:
MariettaO [177]2 years ago
5 0
The vise president of India is M. Venkaiah Naidu
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Limit sodium intake to less than <em><u>2,300mg</u></em> per day. Limit saturated fat intake to less than <em><u>10% </u></em>of daily kilocalories. Limit intake of added sugars to less than<em><u> 5% </u></em>of daily kilocalories. Limit intake of alcohol to less than <em><u>3 drinks </u></em>per day for men or less than <em><u>2 drinks</u></em> per day for women.

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Read 2 more answers
The equilibrium constant, Kc, for the following reaction is 0.967 at 650 K. 2NH3(g) N2(g) 3H2(g) When a sufficiently large sampl
AlekseyPX

Answer: Concentration of NH_3 in the equilibrium mixture is 0.31 M

Explanation:

Equilibrium concentration of H_2 = 0.729 M

The given balanced equilibrium reaction is,

                 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

Initial conc.            x                0           0

At eqm. conc.     (x-2y) M     (y) M   (3y) M

The expression for equilibrium constant for this reaction will be:

3y = 0.729 M

y = 0.243 M

K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}

Now put all the given values in this expression, we get :

K_c=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

0.967=\frac{0.243\times (0.729)^3}{(x-2\times 0.243)^2}

x=0.80

concentration of NH_3 in the equilibrium mixture = 0.80-2\times 0.243=0.31

Thus concentration of NH_3 in the equilibrium mixture is 0.31 M

3 0
3 years ago
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