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dimaraw [331]
3 years ago
10

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

Chemistry
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

               Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

          concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

          concentration 2 = (287 x 1.6) / 412

Simplification

          concentration 2 = 459.2 / 412

Result

           concentration 2 = 1.11 M  

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What is the density of a book that weighs 550 grams and has a volume of 0.5 liters
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Answer:

1.1gcm^-3

Explanation:

density \:  =  \frac{mass}{volume}

0.5l = 0.5*1000

= 500cm^3

Density = 550/500

Density =

{1.1gcm}^{ - 3}

4 0
2 years ago
Which are always the first waves of an earthquake to be detected?
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Answer:

The first kind of body wave is the P wave or primary wave.

Explanation:

This is the fastest kind of seismic wave, and, consequently, the first to 'arrive' at a seismic station.

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5 0
3 years ago
Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the
liq [111]
<span>Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

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8 0
3 years ago
Please HELP!!! Automotive airbags inflate when sodium azide decomposes explosively to its constituent elements. How many grams o
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Answer: 47.2 g of sodium azide

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles of nitrogen}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{24.4L}{22.4L}=1.09moles

The balanced chemical reaction is:

2NaN_3\rightarrow 2Na+3N_2  

According to stoichiometry :  

3 moles of N_2 are produced by = 2 moles of NaN_3

Thus 1.09 moles of N_2 are produced by =\frac{2}{3}\times 1.09=0.73moles  of NaN_3

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