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3 years ago

3 1/3 - 2/5x = 1/5x please help will give branliest

Mathematics

1 answer:

adell [148]3 years ago

3 0

Answer:

5 5/9

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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Write an expression to represent the perimeter of:

malfutka [58]

So perimeter is adding all sides

In this picture, you have all sides, so add them up!

(2a-3)+(3a+1)+(2a) = P

So this expression shows that we're adding all sides that gives us the P, or perimeter :)

8 0

3 years ago

Please help!!! this is due tomorrow!!1!!11!!!1!

Ronch [10]

Answer: m<KHL = 37 degrees.

m<GHK = 53 degrees

Step-by-step explanation:

<CHD and <KHL are vertical angles. They are equal in measure. m<CHD is 37 degrees, so m<KHL is also 37 degrees.

Notice <GHL is a 90 degree angle (because the lines that form it are perpendicular) and <GHL is made up of two angles: <GHK and <KHL.

m<GHK + m<KHL (37) = m< GHL (90 degrees)

Subtract 37 from both sides.

m<GHK = 53 degrees

7 0

2 years ago

What factors does Jenna need to model for the sides?

mojhsa [17]

Do you know the muffin man 2*+%9272

8 0

2 years ago

Read 2 more answers

PLEASE PLEAE PLEASE HELP

scoundrel [369]

She bought 4 coffees! :)

7 0

2 years ago

You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2

defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

$P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715$

Probability a unit is defective and from manufacturer A:

2% of 43%. So

$P(A \cap B) = 0.02*0.43 = 0.0086$

What is the probability that it came from manufacturer A?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015$

0.5015 = 50.15% probability that it came from manufacturer A.

4 0

2 years ago