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Anestetic [448]
4 years ago
5

How many pt are there in 10 qt

Mathematics
1 answer:
nataly862011 [7]4 years ago
8 0
The answer is 20 pt. Hope this helped
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6 divided by 156 whats the remainder<br><img src="https://tex.z-dn.net/?f=6%20%20%5Cdiv%20156%20%3D%20" id="TexFormula1" title="
brilliants [131]
I divided 6 by 156 and I got 0.0384615385 that's what I got
3 0
3 years ago
Find the missing side x
Artist 52 [7]

Answer:

x = 21.52

Step-by-step explanation:

Given:

hypotenuse (That has to be found out)

Side adjacent to the given angle

and an angle,

Hence we can say that Cos ratio would be used;

Cos(28) = 19 / x

x = 19 / Cos(28)

x = 21.52

Hope this helps!

8 0
3 years ago
The volume of a cylinder is 576 cubic inches. The radius of the circular base is 4 inches. What is the height of the cylinder?
Ede4ka [16]

Answer:

11.46 inches

Step-by-step explanation:

h=V

πr2=576

π·42≈11.45916in

(round)

4 0
3 years ago
Read 2 more answers
What’s the endpoint of- (7,10), (1,-7)
Aleks04 [339]

Answer:

0.7 /-0.14

Step-by-step explanation:

Use calculator and press the pecahan and change it to decimal

8 0
3 years ago
Suppose that the weight of navel oranges is normally distributed with a mean µµ = 8 ounces, and a standard deviation σσ = 1.5 ou
monitta

Answer:

Hello some parts of your question is missing below is the missing part

c. If you randomly select a navel orange, what is the probability that it weighs between6.2 and 7 ounces

Answer: A) 0.0099

              B) 0.6796

              C) 0.13956

Step-by-step explanation:

weight of Navel oranges evenly distributed

mean ( u ) = 8 ounces

std ( б )= 1.5

navel oranges = X

A ) percentage of oranges weighing more than 11.5 ounces

P( x > 11.5 ) = P ( \frac{x - u}{ std} > \frac{11.5-8}{1.5} )

                   = P ( Z > 2.33 ) = 0.0099

                   = 0.9%

B) percentage of oranges weighing less than 8.7 ounces

  P( x < 8.7 ) = P ( \frac{x - u}{ std} > \frac{8.7-8}{1.5} )

                    = P ( Z < 0.4667 ) = 0.6796

                    = 67.96%

C ) probability of orange selected weighing between 6.2 and 7 ounces?

P ( 6.2 < X < 7 ) = P (\frac{6.2-8}{1.5} <  \frac{x - u}{ std} < \frac{7-8}{1.5} )

                          = P ( -1.2 < Z < -0.66 )

                          = Ф ( -0.66 ) - Ф(-1.2) = 0.13956

7 0
4 years ago
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