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musickatia [10]
4 years ago
7

A 3-liter container has a pressure of 4 atmospheres. The container is sent underground, with resulting compression into 2 L. App

lying Boyle's Law, what will the new pressure be? choices: 2.3 atm 8 atm 6 atm 1.5 atm
Physics
1 answer:
monitta4 years ago
4 0

Answer:

6 atm

Explanation:

PV = PV

(4 atm) (3 L) = P (2 L)

P = 6 atm

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Where would you most likely find regional metamorphism? associated with a mountain belt associated with a volcano associated wit
vladimir1956 [14]
Regional metamorphism is a type of metamorphism in which the minerals and the textures of the rocks are changed or altered due to the effect of pressure and heat over a wide area or region.
This type of metamorphism often results in metamorphic rocks that are strongly foliated.
Metamorphism usually occurs in the folds of thrust mountain belts.

Answer: You would most likely find regional metamorphism associated with a mountain belt.

5 0
3 years ago
Read 2 more answers
A 185 g block is pressed against a spring of force constant 1.60 kN/m until the block compresses the spring 10.0 cm. The spring
denis-greek [22]

Answer:

d = 5.10 m

Explanation:

As we know that here on the plane of the inclined there is no frictional force

So in these cases we can say that total mechanical energy will always remains conserved

so here we can say that

spring potential energy = gravitational potential energy of the block

as we know from the formula

\frac{1}{2}kx^2 = mgh

now plug in the values in it

\frac{1}{2}(1.60 \times 10^3)(0.10)^2 = (0.185)(9.81)h

8 = 1.81 h

h = 4.42 m

now as we know that the angle of inclination is 60 degree and height raised is 4.42 m

so here maximum distance moved along the inclined plane will be

\frac{h}{d} = sin60

d = \frac{h}{sin60}

d = \frac{4.42}{sin60} = 5.10 m

6 0
3 years ago
Starting from rest near the surface of the Earth, a 25-kg beam slides 12 m down a vertical pine tree, and has a speed of 6 m/s j
Mamont248 [21]

Answer:

The frictional force acting on the bear during the slide is 207.5 N

Explanation:

Given;

mass of beam, m = 25-kg

vertical height, h = 12 m

speed of fall, v =  6 m/s

Change in potential energy of the beam:

ΔP.E = -mgh = - 25 x 9.8 x 12 = -2940 J

Change in kinetic energy of the beam:

Δ K.E = ¹/₂mv² = ¹/₂ x 25 x (6)² = 450 J

Change in thermal energy of the system due to friction:

ΔE = - (ΔP.E  + Δ K.E)

ΔE = - (-2940 J + 450 J)

ΔE = 2940 J - 450 J = 2490 J

Frictional force (in N) acting on the bear during the slide:

F x d = Fk x h = ΔE

Where;

Fk is the frictional force

Fk = ΔE/h

Fk = 2490J / 12m

Fk = 207.5 N

Therefore, the frictional force acting on the bear during the slide is 207.5 N

3 0
3 years ago
A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c
Y_Kistochka [10]
Given:
m = 555 g, the mass of water in the calorimeter
ΔT = 39.5 - 20.5 = 19 °C, temperature change
c = 4.18 J/(°C-g), specific heat of  water

Assume that all generated heat goes into heating the water.
Then the energy released is
Q = mcΔT
    = (555 g)*(4.18 J/(°C-g)*(19 °C)
    = 44,078.1 J
    = 44,100 J (approximately)

Answer:  44,100 J

3 0
3 years ago
Name the following ionic bonds.
Gennadij [26K]
D !.!.!.!.!.!!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!!..!!..!
7 0
3 years ago
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