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musickatia [10]
4 years ago
7

A 3-liter container has a pressure of 4 atmospheres. The container is sent underground, with resulting compression into 2 L. App

lying Boyle's Law, what will the new pressure be? choices: 2.3 atm 8 atm 6 atm 1.5 atm
Physics
1 answer:
monitta4 years ago
4 0

Answer:

6 atm

Explanation:

PV = PV

(4 atm) (3 L) = P (2 L)

P = 6 atm

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Sarah is 14 years old and skips school twice a week without any written explanation. What can she be charged with?
harina [27]

Answer:

Too many people are unaware or indifferent to that.” Fines can cost up to $500 per truancy, due within 30 days unless a judge gives an extension. For many students and families, it's another debt they can't pay. And if fines aren't paid, they can convert into an arrest warrant when a student turns 17.

Explanation:

5 0
3 years ago
a car is travelig at 20.0 m/s when the driver applies the brakes and comes to a stop. if the car slows down uniformly with an ac
alisha [4.7K]

Since acceleration is constant, we can use the formula

v² - u² = 2a ∆x

where v = final velocity, u = initial velocity, a = acceleration, and ∆x = displacement. Then

0² - (20.0 m/s)² = 2 (-4.20 m/s²) ∆x

⇒   ∆x = (20.0 m/s)² / (8.40 m/s²) ≈ 47.6 m

3 0
3 years ago
A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i
murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

v_o = 21.8 m/s

v is speed of sound = 343 m/s

Thus;

f' = 46200(1 - (21/343))

f' = 43371.4285 Hz

In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

f" = f'/(1 + (v_o/v))

f" = 43371.4285/(1 + (21.8/343))

f" = 40779.61 Hz

4 0
3 years ago
Use bisection to determine the drag coefficient needed so that a 65kg bungee jumper has a velocity of 35m/s after 4.5s of free f
kodGreya [7K]

Answer:

the drag coefficient = 0.2703126

Explanation:

see the attached file

4 0
3 years ago
A particle is confined to a one-dimensional box that is 50 pm long. What is the smallest possible uncertainty in momentum for th
nevsk [136]

Answer:

The smallest possibility is 0.01E-22kgm/s

Explanation:

Using

Momentum= h/4πx

= 6.6x 10^-34Js/ 4(3.142* 50*10-12m)

= 0.01*10^-22kgm/s

6 0
3 years ago
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