All categories

3 years ago

A hobby rocket reaches a height of 72.3 meters and lands 111 meters from the launch point

1 answer:

8 0

Using the following formulas for projectile motion:

Height, H = ( Vo^2 * sin theta^2 )/g

Range, R = ( Vo^2 * sin 2*theta )/g

Rearranging in terms of Vo^2:

Vo^2 = gH / sin theta^2

Vo^2 = gR / sin 2*theta

Equating the two formulas to each other to solve for the angle theta:

gR / sin 2*theta = gH / sin theta^2

Substituting the given values:

(9.8)(111) / sin 2*theta = (9.8)(72.3) / sin theta^2
angle = 52.36 degrees

Therefore, the angle of launch is approximately 52.36 degrees.

You might be interested in

You wiggle a string, that is fixed to a wall at the other end, creating a sinusoidal wave with a frequency of 2.00 Hz and an amp

allochka39001 [22]

Answer:hhhkkzkxixuhhhdhhdhdhhhdhhhshsbbsbzhhdhhdhhhshhhdhhdusudhggdydyydhshdhgddhsjsudhdhhdh

Explanation:NzjzjhbxxhzhdghsjshshhHjajskajakakakakaiaiaiijhayayayagayahahah

4 0

3 years ago

An experiment is designed to see if sleep affects the number of vocabulary words subjects can remember. The dependent variable i

Kaylis [27]

The dependent variable is: "number of vocabulary words subjects can remember"

<h3>Which is the dependent variable?</h3>

In an experiment, we basically see how changing one variable affects another variable.

In this case, the experiment is:

" if sleep affects the number of vocabulary words subjects can remember."

Then the hours of sleep would be the independent variable (the one that the scientist can change) and the number of vocabulary words subjects can remember is the dependent variable (that depends on the independent variable).

So the correct answer is:

"number of vocabulary words subjects can remember"

If you want to learn more about variables:

brainly.com/question/15246027

#SPJ1

7 0

2 years ago

When the car was stopped by the tree, its change in velocity during the collision was-6 meters/second. This change in

HACTEHA [7]

Answer: -3 meters/second^2.

Explanation:

3 0

3 years ago

Three equal point charges, each with charge 1.15 μCμC , are placed at the vertices of an equilateral triangle whose sides are of

julsineya [31]

Answer:

$U=50.96J$

Explanation:

The electrostatic potential energy for pair of charge is given by

U=1/4π∈₀×(q₁q₂/r)

Hence for a system of three charges the electrostatic potential energy can be found by adding up the potential energy for all possible pairs or charges.For three equal charges on the corners of an equilateral triangle,the electrostatic potential energy is given by:

U=1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)+1/4π∈₀×(q²/r)

U=3×1/4π∈₀×(q²/r)

Substitute given values

$U=3\frac{1}{4\pi E_{o} }\frac{q^{2} }{r}\\ U=3\frac{1}{4\pi8.85*10^{-12} }\frac{(1.15*10^{-6}C )^{2} }{0.0007m}\\ U=50.96J$

8 0

3 years ago

Two resistors A and B are arranged in series in one branch of a parallel arrangement. The other branch contains a single resisto

Ganezh [65]

Answer:

Explanation:

A and B are in series , Total resistance = Ra + Rb

This resistance is in parallel with single resistor C

Equivalent resistance Re = Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )]

Now this combination is in series in single resistance D .

Total resistance = Rd + Re

= Rd + { Rc x ( Ra + Rb ) / [Rc + ( Ra + Rb )] }

5 0

2 years ago