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3 years ago

4. A spring is stretched 0.5 m from equilibrium. The force constant (k) of the

Physics

2 answers:

makkiz [27]3 years ago

8 0

Answer:

31.25

Explanation:

The formula for the potential energy of a spring is $\frac{1}{2}kx^2$ , where x is the distance in meters the spring is stretched. Plugging in the numbers that you are given, you get $\frac{1}{2}\cdot 250\cdot 0.25=31.25$ . Hope this helps!

hodyreva [135]3 years ago

8 0

31.25 hope this helps:)

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kozerog [31]

We have that The Density and Volume is given as

$\rho=0.67\\\\\V=30cm^3$

The factors that affect Density are Mass and Volume

From the question we are told that

The piece of wood shown above has a mass of 20 grams.

Wood parameters

2cm

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Generally the equation for the Volume is mathematically given as

$V=L*B*H\\\\\V=2*5*3\\\\V=30cm^3$

Generally the equation for the Density is mathematically given as

$\rho=\frac{m}{v}\\\\\\rho=\frac{20}{30}\\\\\rho=0.67$

Therefore the factors that affect Density are Mass and Volume

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2 years ago

Determine a valid way of finding the wire’s diameter if you know the resistivity of the material, \rho , and can measure the cur

olganol [36]

Answer:

To find the diameter of the wire, when the following are given:

Resistivity of the material (Rho), Current flowing in the conductor, I, Potential difference across the conductor ends, V, and length of the wire/conductor, L.

Using the ohm's law,

Resistance R = (rho*L)/A

R = V/I.

Crossectional area of the wire A = π*square of radius

Radius = sqrt(A/π)

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Making A the subject of the formular

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From the result of A, Diameter can be determined using

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Explanation:

Error and uncertainty can be measured varying the value of the parameters used and calculating different values of the diameters. Compare the values using standard deviation

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3 years ago

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Answer:

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Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

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Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

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And

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