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chubhunter [2.5K]
4 years ago
14

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.

5 N and it is acting with an effective lever arm of 1.95 cm , what is the torque that the muscle produces on the wrist
Physics
1 answer:
zmey [24]4 years ago
3 0

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

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A Ford Taurus driven 12,000 miles a year will use about 650 gal of gasoline compared to a Ford Explorer that would use 850 gal.
irga5000 [103]

Answer:

19 800 lbm of carbon dioxide more.

Explanation:

<u>Taurus</u>

Amount of gasoline used in 5 years = 650 ga/year * 5 years = 3250 ga

amount of carbon dioxide released = 19.8 lbm/ga * 3250 ga = 64 350 lbm

<u>Explorer</u>

Amount of gasoline used in 5 years = 850 ga/year * 5 years = 4250 ga

amount of carbon dioxide released = 19.8 lbm/ga * 4250 ga = 84 150 lbm

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4 0
4 years ago
Analysis of the relationship between the fuel economy​ (mpg) and engine size​ (liters) for 35 models of cars produces the regres
kvasek [131]

Answer:

Gas mileage is 17.29

Explanation:

Given data:

The total number of the model is 35

The total size of the engine is 5 ltr

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36.44 - 3.829\times engine\ size

From the information given in question we have

Regression equation is : model- mpg = 36.44 - 3.829\times engine\ size

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Gas mileage is 17.29

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3 years ago
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Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The f
Pavlova-9 [17]

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

<u>a) Determine the principal stresses and shear stress</u>

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

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б1 = 32.62mPa  

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attached below is the remaining part of the solution

3 0
3 years ago
A box of books weighing 305 N is shoved
Anna [14]

Answer:

3.1 s

Explanation:

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acceleration due to gravity (g) = 9.81 m/s^{2}

coefficient of friction Uk= 0.59

time (t) = ?

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now lets get the acceleration from the summation of the horizontal forces

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516cos32 - (0.59 x 677.6) = 31 x a

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a =  1.22m/s^{2}

now that we have our acceleration we can get the time from the equation of motion

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u ( initial velocity ) = 0 because the box was initially at rest

5.82 = (0 x t ) + (0.5 x 1.22 x t^{2})

5.82 = 0.61t^{2}

t = 3.1 s

5 0
3 years ago
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