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chubhunter [2.5K]
3 years ago
14

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 43.

5 N and it is acting with an effective lever arm of 1.95 cm , what is the torque that the muscle produces on the wrist
Physics
1 answer:
zmey [24]3 years ago
3 0

To solve this problem, we must take two important steps. First we will convert all the given units, to international system. Later we will define the torque, which is given as the product between the radius of application of the force and the Force acting on the body. Mathematically the latter is,

\tau = r F

Here,

r = Radius

F = Force

Now the units,

r = 1.95cm = 1.95*10^{-2}m

Replacing,

\tau = (1.95*10^{-2})(43.5N)

\tau = 0.8483N\cdot m

Therefore the torque that the muscle produces on the wrist is 0.85N\cdot m

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Explanation:

8) Acceleration of the car is determined by finding the ratio of change in velocity to the time taken for the change in velocity. As here the initial velocity is 18.5 m/s and the final velocity is 46.1 m/s, then in 2.47 seconds, the acceleration is

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So the average acceleration of the sprinter is 2 m/s².

12)Since the acceleration of the stroller is given as 0.6 m/s². And the initial velocity is given as zero. So for the time of 4.75 minutes, the velocity will be equal to the final velocity.

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v = u +at

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v = u +at = 0+ (50 t)

28 = 50 t

t = 28/50 = 0.56 s

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