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DIA [1.3K]
3 years ago
9

Which of the following situations would produce an average velocity of zero?

Physics
1 answer:
MariettaO [177]3 years ago
4 0
The correct answer is A
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A centrifuge in a forensics laboratory rotates at an angular speed of 3,700 rev/min. When switched off, it rotates 46.0 times be
ra1l [238]

Answer:

Explanation:

Given,

initial angular speed, ω = 3,700 rev/min

                                      = 3700\times \dfrac{2\pi}{60}=387.27\ rad/s

final angular speed = 0 rad/s

Number of time it rotates= 46 times

angular displacement, θ = 2π x 46 = 92 π

Angular acceleration

\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}

\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}

\alpha = -259.28 rad/s^2

3 0
3 years ago
Calculate the recoil speed of a 1.4 kg rifle shooting 0.006 kg bullets with muzzle speed of 800 m/a.3.43 m/s
Angelina_Jolie [31]

Answer:

a) 3.43 m/s

Explanation:

Due to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the bullet is shot is zero, because they are both at rest, so:

p_i = 0

Instead the total momentum of the system after the shot is:

p_f = mv+MV

where:

m = 0.006 kg is the mass of the bullet

M = 1.4 kg is the mass of the rifle

v = 800 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

The total momentum is conserved, therefore we can write:

p_i = p_f

Which means:

0=mv+MV

Solving for V, we can find the recoil velocity of the rifle:

V=-\frac{mv}{M}=-\frac{(0.006)(800)}{1.4}=-3.43 m/s

where the negative sign indicates that the velocity is opposite to direction of the bullet: so the recoil speed is

a) 3.43 m/s

5 0
3 years ago
An X-ray tube emits X-rays with a wavelength of 1.0 x 10-11 m. Calculate the potential that must be applied across the X-ray tub
sergey [27]

Answer:

1.24 x 10 to the 5 ev = 124,000 ev          its B

Explanation:

E = hc/lambda = 1.24 ev-micrometer/1.0x10 to the -5 micrometers = 1.24 x 10 to the 5 ev = 124,000 ev

h = Planck's constant = 6.626 × 10 to the -34 joule·s

c = speed of light = 2.998 × 10 to the 8 m/s

lambda is the given wavelength

E is the desired photon energy

3 0
3 years ago
Read 2 more answers
What property of light shown in the picture?
kupik [55]

Answer:

Explanation:

Reflection

8 0
2 years ago
Read 2 more answers
Mark all the fermions a) Proton b) Electron c)Anti-top d) Gluon e) Tau Neutrino
aliya0001 [1]

Answer:

(a) Proton, (b) Electron (c) tau neutrino.

Explanation:

Elementary particles are the particles without any sub-structure which means they are not composed of other particles.

The elementary particles are classified into three categories which are discussed below:

(1) Quarks: up, down, top, bottom, strange, and charm.

(2) Leptons: electrons, electron neutrino, muon, muon neutrino, tau, tau neutrino.

(3) Bosons: Guon, photons Z bosons, W bosons, Higgs.

Fermions are particles that follow Fermi-Dirac statistics. Fermions consist of all the quarks and leptons. And fermions can also be categorized in elementary particles such as electrons and protons.

Therefore, the fermions in the given question are proton, electron, and tau neutrino.

5 0
3 years ago
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