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3 years ago

Which of the following are not eukaryotes

Chemistry

1 answer:

kodGreya [7K]3 years ago

3 0

Answer:

Bacteria

Explanation:

Eukaryotic cells have membrane-bound organelles and eukaryotic cells have a nucleus that contains the genetic material.

examples: plants, fungi, and animals.

prokaryotic cells they do have a membrane-bound organelles,nucleus is absent and their genetic material free and floating is present in the nucleoid region.

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A runner runs 4339 ft in 7.45 minutes. What is the runner's average speed in miles per hou 6.62 mi/hr O 0.110 mi/hr 6.618 mi/h e

slavikrds [6]

<u>Answer:</u> The average speed of the runner is 6.618 miles/hr

<u>Explanation:</u>

Average speed is defined as the ratio of total distance traveled to the total time taken.

To calculate the average speed of the runner, we use the equation:

$\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}$

We are given:

Distance traveled = 4339 ft

Time taken = 7.45 mins

Putting values in above equation, we get:

$\text{Average speed of runner}=\frac{4330ft}{7.45min}=582.42ft/min$

To convert the speed into miles per hour, we use the conversion factors:

1 mile = 5280 ft

1 hr = 60 mins

Converting the speed into miles per hour, we get:

$\Rightarrow \frac{528.42ft}{min}\times (\frac{1miles}{5280ft})\times (\frac{60min}{1hr})\\\\\Rightarrow 6.618mil/hr$

Hence, the average speed of the runner is 6.618 miles/hr

6 0

3 years ago

_Nal+ _CaCl2 what's the answer ?

Sindrei [870]

2Nal+CaCl2 should be right

5 0

3 years ago

Which describes a homogeneous mixture?

Rom4ik [11]

Answer:

A solution dissolves in a solute to make a solvent.

Explanation:

The image is from Google

6 0

3 years ago

Calculate the change in the standard entropy of the system, delta s degree for the synthesis of ammonia from N_2(g) and H_2(g) a

Svet_ta [14]

Answer:

$\Delta S^{0}$ for the reaction is -198.762 J/K

Explanation:

$N_{2}(g)+3H_{2}(g)\rightarrow 2NH_{3}(g)$

Standard change in entropy for the system ( $\Delta S^{0}$ ) is given by-

$\Delta S^{0}=[2moles\times S^{0}(NH_{3})_{g}]-[1mole\times S^{0}(N_{2})_{g}]-[3\times S^{0}(H_{2})_{g}]$

where $S^{0}$ represents standard entropy.

Here $S^{0}(NH_{3})_{g}=192.45J/(K.mol)$ , $S^{0}(N_{2})_{g}=191.61J/(K.mol)$ and $S^{0}(H_{2})_{g}=130.684J/(K.mol)$

So, $\Delta S^{0}=[2\times 192.45]-[1\times 191.61]-[3\times 130.684]J/K=-198.762J/K$

3 0

3 years ago

Magnesium oxide can be made by heating magnesium metal in the presence of the oxygen. The balanced equation for the reaction is

erik [133]

Answer : The percent yield of $MgO$ is, 64.13 %

Solution : Given,

Mass of Mg = 10 g

Mass of $O_2$ = 6 g

Molar mass of Mg = 24 g/mole

Molar mass of $O_2$ = 32 g/mole

Molar mass of MgO = 40 g/mole

First we have to calculate the moles of Mg and $O_2$ .

$\text{ Moles of }Mg=\frac{\text{ Mass of }Mg}{\text{ Molar mass of }Mg}=\frac{10g}{24g/mole}=0.4167moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{6g}{32g/mole}=0.1875moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2Mg(s)+O_2(g)\rightarrow 2MgO(s)$

From the balanced reaction we conclude that

As, 1 mole of $O_2$ react with 2 mole of $Mg$

So, 0.1875 moles of $O_2$ react with $0.1875\times 2=0.375$ moles of $Mg$

From this we conclude that, $Mg$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $MgO$

From the reaction, we conclude that

As, 1 mole of $O_2$ react to give 2 mole of $MgO$

So, 0.1875 moles of $O_2$ react to give $0.1875\times 2=0.375$ moles of $MgO$

Now we have to calculate the mass of $MgO$

$\text{ Mass of }MgO=\text{ Moles of }MgO\times \text{ Molar mass of }MgO$