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Oxana [17]
3 years ago
6

What’s the answer for #9

Chemistry
1 answer:
zheka24 [161]3 years ago
4 0
Freezer and refrigerator--> Too cold for most bacteria to grow (reproduce). Oven --> too hot for bacteria to survive
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Say I grab a bunch of aluminum foil (9.5g) and ball it up. Aluminum has a specific heat of .9J/g*C. How much would the aluminum’
Brrunno [24]

Answer:

ΔT = 0.78 °C

Explanation:

Given data:

Mass of Al = 9.5 g

Specific heat capacity of Al = 0.9 J/g.°C

Temperature change = ?

Heat added = 67 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

67 J = 9.5 g × 0.9 j/g.°C × ΔT

67 J = 85.5 j/°C × ΔT

ΔT = 67 J  /  85.5 j/°C

ΔT = 0.78 °C

7 0
3 years ago
PLZZZZ HELPPPPPPPPPPPP<br><br> Which correctly describes molecule "a" in this diagram
pogonyaev

Answer is: adenosine triphosphate.

ATP is made of three components: the triphosphate (P), the sugar ribose and a nitrogenous base (adenine).

ATP is short for adenosine triphosphate

Adenosine triphosphate converts to either the adenosine diphosphate (ADP) or adenosine monophosphate (AMP), in this process energy is released.  

4 0
3 years ago
Read 2 more answers
How can an atom that has seven valence electrons complete its outermost level
GaryK [48]
It can form a covalent bond with a hydrogen bond that has one valence electron to have eight valence electrons and become stable.
3 0
3 years ago
Read 2 more answers
In the chemical symbol for nitrogen gas, N2, what does the “2” represent?
Vladimir79 [104]
The 2 represets 2 nitrogen gas atoms
4 0
4 years ago
Suppose 7.05 g of zinc iodide is dissolved in 150. mL of a 0.20M aqueous solution of potassium carbonate. Calculate the final mo
sasho [114]

Answer:

M=0.294M

Explanation:

Hello!

In this case, since the molarity of the iodide ion is computed by dividing the moles of iodide ions by the volume of solution in liters (0.150 L), we first need to compute the moles of zinc iodide (ZnI2) by using its molar mass and then using a mole ratio of 1 mol of zinc iodide to 2 mol of iodide ion:

n_{I^-}=7.05gZnI_2*\frac{1molZnI_2}{319.22 gZnI_2}*\frac{2molI^-}{1molZnI_2}=0.0442molI^-

Therefore, the resulting molarity turns out:

M=\frac{0.0442molI^-}{0.150L} \\\\M=0.294M

Best regards!

4 0
3 years ago
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