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Sphinxa [80]
3 years ago
15

Which of the following measurements is expressed to three significant figures?

Chemistry
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

D

Explanation:

it goes past the decimal three places

LenKa [72]3 years ago
4 0

Answer:

C

Explanation:

A is  1 sig fig

B is 4 sig fig

C is 3 sig fig

D is 2 sig fig

Decimal places do not necessarily determine sig figs.

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Osmosis is the process responsible for carrying nutrients and water from groundwater supplies to the upper parts of trees. The o
Nady [450]

Answer:

0.825 M

Explanation:

The osmotic pressure is a colligative property, that can be calculated using the following expression.

π = M × R × T

where,

π is the osmotic pressure

M is the molarity

R is the ideal gas constant

T is the absolute temperature (24°C + 273 = 297 K)

M = π / R × T = 20.1 atm / (0.08206 atm.L/mol.K) × 297 K = 0.825 M

5 0
3 years ago
When water reaches the metastable state, the phase of water will be?​
Jet001 [13]

Answer:

water, when the metastable state is reached, is cooled below the zero temperature. It freezes abruptly. this is called metastable. They are not at equilibrium per se; as at negative temperatures the only equilibrium state of water is ice.

Explanation:

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3 years ago
From his experiment j.j. Thomson concluded that
iragen [17]
Particles as small as atoms exist.
3 0
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What are the challenges for a "sustainable" world of lithium ion batteries?
Neporo4naja [7]

The Lithium-ion Battery Problem

Overheating. They overheat and explode if charged too fast.

Short life time. They die after less than 1,000 charge/discharge cycles.

Flammable. They use chemicals that are flammable. ...

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7 0
2 years ago
Burning 12.00 g of an oxoacid produces 17.95 g of carbon dioxide and 4.87 g of water. Consider that 0.25
Veseljchak [2.6K]

Answer: The molecular formula will be C_6H_6O_6

Explanation:

Mass of CO_2 = 17.95 g

Mass of H_2O= 4.87 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 17.95 g of carbon dioxide, =\frac{12}{44}\times 17.95=4.89g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 4.87 g of water, =\frac{2}{18}\times 4.87=0.541g of hydrogen will be contained.

Mass of oxygen in the compound = (12.00) - (4.89+0.541) = 6.57 g

Mass of C = 4.89 g

Mass of H =  0.541 g

Mass of O = 6.57 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.89g}{12g/mole}=0.407moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.541g}{1g/mole}=0.541moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{6.57g}{16g/mole}=0.410moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.407}{0.407}=1

For H =\frac{0.541}{0.407}=1

For O = \frac{0.410}{0.407}=1

The ratio of C : H : O = 1: 1  : 1

Hence the empirical formula is CHO.

Hence the empirical formula is CHO

The empirical weight of CHO = 1(12)+1(1)+1(16)= 29 g.

If 0.25 moles has mass of 44.0 g

Thus 1 mole has mass of = \frac{44.0}{0.25}\times 1=176g

Thus molecular mass is 176 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{176g}{29g}=6

The molecular formula will be=6\times CHO=C_6H_6O_6

5 0
3 years ago
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