Answer:
Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.
CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.
Explanation:
In the reaction:
Ni(s) + CuCl₂(aq) → Cu(s) + NiCl₂(aq)
Ni (s) is oxidized because it loses electrons. This makes it the reducing agent.
------------> Ni (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.
-------------> In NiCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, nickel must have an oxidation number of +2 to balance the charges.
--------------> Because nickel goes from an oxidation number of 0 to +2, this indicates that it lost electrons and was reduced.
CuCl₂ (aq) is reduced because it gains electrons. This makes it the oxidizing agent.
-------------> In CuCl₂ (aq), chlorine must have an oxidation number of -1, and because there are two chorine atoms, they contribute a total -2 charge. To make the overall charge neutral, copper must have an oxidation number of +2 to balance the charges.
------------> Cu (s) has an oxidation number of 0. All lone atoms (that are not ions) have a 0 oxidation number.
--------------> Because copper goes from an oxidation number of +2 to 0, this indicates that it gained electrons and was oxidized.
I believe you may be referring to cold welding? This is when two pieces of metal are put together in a vacuum and are thus permanently "cold-welded" together
Answer:
I^- or Cl^-
Explanation:
A nucleophile is any reagent that donates an unshared pair of electrons to form a new covalent bond. Nucleophiles are mostly bases also. Nucleophilicity is a kinetic property, it refers to the rate at which a nucleophile replaces a leaving group from an alkyl halide.
Looking at the options, Cl^- and I^- are the best nucleophiles among the options provided in the question.
<h3><u>Answer;</u></h3>
pOH = 3.08
<h3><u>Explanation;</u></h3>
NX3 + H2O <----> NHX3+ + OH-
Kb = 4.0 x 10^-6
Kb = c(NH₄⁺) · c(OH⁻) ÷ c(NH₃).
c(NH₄⁺) = c(OH⁻) = x.
x² = Kb · c(NH₃)
x² = 4.0 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.
x = c(OH⁻) = √(7.0 × 10⁻⁷)
= 8.367 × 10⁻⁴
pOH = -log(c(OH⁻))
=- log ( 8.367 × 10⁻⁴)
<u>= 3.08</u>
Answer:
Tea is getting hot on the stove.
2) As the tea and water gets hot, some combined molecules of tea and water will escape from the teapot.
3) Those escaped molecules now have the entire free space of the entire room to float around in, which they do (because they have high kinetic energy due to being heated).
4) Hence, in this scenario, your nose will detect a few of those molecules and you smell hot or warm tea.
5) Cold tea would be a different story. Cold beverages like cold tea do not have the kinetic energy where molecules can 'break free' of the surrounding container. Someone could be sitting in the room having a can or bottle of cold tea and you would not notice that when you walked in the door.
