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9966 [12]
2 years ago
6

1. How many moles are in 15.5 g of SO2

Chemistry
1 answer:
Maurinko [17]2 years ago
3 0

1. The number of mole in 15.5 g of SO₂ is 0.242 mole

2. The mass of 1.50 mole of C₃H₈ is 66 g

3. The number of mole of NH₃ that contains 1.5×10²³ molecules is 0.249 moles

4. The mass of NaCl that contains 2.5×10²⁵ formula units is 2429.4 g

5. The number of molecules present in 3.6 moles of CO₂ is 2.167×10²⁴ molecules

<h3>1. How to determine the mole of SO₂</h3>
  • Mass of SO₂ = 15.5 g
  • Molar mass of SO₂ = 32 + (2×16) = 64 g/mol
  • Mole of SO₂ =?

Mole = mass / molar mass

Mole of SO₂ = 15.5 / 64

Mole of SO₂ = 0.242 mole

<h3>2. How to determine the mass of C₃H₈</h3>
  • Mole of C₃H₈ = 1.5 mole
  • Molar mass of C₃H₈ = 44 g/mol
  • Mass of C₃H₈ =?

Mass = mole × molar mass

Mass of C₃H₈ = 1.5 × 44

Mass of C₃H₈ = 66 g

<h3>3. How to determine the mole of NH₃ </h3>

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole of NH₃

Therefore,

1.5×10²³ molecules = 1.5×10²³ / 6.02×10²³

1.5×10²³ molecules = 0.249 mole of NH₃

<h3>4. How to determine the mass of NaCl </h3>

6.02×10²³ units = 58.5 g of NaCl

Therefore,

2.5×10²⁵ units = (2.5×10²⁵ × 58.5) / 6.02×10²³

2.5×10²⁵ units = 2429.4 g of NaCl

<h3>5. How to determine the number of molecules </h3>

1 mole of CO₂ = 6.02×10²³ molecules

Therefore,

3.6 moles of CO₂ = 3.6 × 6.02×10²³

3.6 moles of CO₂ = 2.167×10²⁴ molecules

Learn more about Avogadro's number:

brainly.com/question/26141731

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Please helpWhat’s the pH of a solution of ammonia that has a concentration of 0.335 M? The Kb of ammonia is
natta225 [31]

From the calculation, the pH of the solution is 4.85.

<h3>What is the pH?</h3>

The pH is defined as the hydrogen ion concentration of the solution. We have the ICE table as;

         HA    +    H2O ⇔     H3O^+    +    A^-

I       0.335                          0                0

C     -x                                  +x              +x

E   0.335 - x                         x                x

Ka = 1 * 10^-14/Kb

Ka = 1 * 10^-14/1.8 × 10^–5

Ka = 5.56 * 10^-10

Ka = [H3O^+] [A^-]/[HA]

But  [H3O^+] = [A^-] = x

5.56 * 10^-10 = x^2/ 0.335 - x

5.56 * 10^-10(0.335 - x ) =  x^2

1.86  * 10^-10 - 5.56 * 10^-10x =  x^2

x^2 + 5.56 * 10^-10x - 1.86  * 10^-10 = 0

x=0.000014 M

Now;

pH = -log 0.000014 M

pH = 4.85

Learn more about pH:brainly.com/question/15289741

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Which of the models shown below best represents the modern understanding of the structure of the atom?
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The atomic mass of an element most nearly reflects the elements total number of
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<h3> the atomic mass is the number of protons and neutrons in an element added together</h3>

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Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the
AveGali [126]

<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.

<u>Explanation:</u>

The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

The net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)

The ionic equation follows:

Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)

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