Answer: Hotspot: A hotspot is a physical location where people can access the Internet, typically using Wi-Fi, via a wireless local area network (WLAN) with a router connected to an Internet service provider. ... While many public hotspots offer free wireless access on an open network, others require payment.
A hot spot is an area on Earth over a mantle plume or an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma. The magma plume causes melting and thinning of the rocky crust and widespread volcanic activity.
Explanation: MY own word's.
Answer : The correct option is, forms of the same element that differ in the number of neutrons in each atom
Explanation :
Isotopes : It is defined as the forms of same element that have the same number of protons and electrons but differ in the number of neutrons.
For example : Carbon-12, carbon-13 and carbon-14 is an isotopes due to the same number of protons and electrons and different number of neutrons.
Carbon-12
Atomic number = 6
Atomic mass = 12
Atomic number = Number of protons = Number of electrons = 6
Number of neutrons = Atomic mass - Atomic number = 12 - 6 = 6
Carbon-13
Atomic number = 6
Atomic mass = 13
Atomic number = Number of protons = Number of electrons = 6
Number of neutrons = Atomic mass - Atomic number = 13 - 6 = 7
Carbon-14
Atomic number = 6
Atomic mass = 14
Atomic number = Number of protons = Number of electrons = 6
Number of neutrons = Atomic mass - Atomic number = 14 - 6 = 8
1. balanced
2. balanced
3. unbalanced
4. balanced
this is the answers and working out to both questions
Answer:
The answer to your question is 11.0 L
Explanation:
Data
[Concentration 1] = 12 M
Volume 1 = 3.0 L
[Concentration 2] = 3.25 M
Volume 2 = ?
Process
1.- To solve this problem, use the dilution formula
Concentration 1 x Volume 1 = Concentration 2 x Volume 2
- Solve for Volume 2
Volume 2 = Concentration 1 x Volume 1 / Concentration 2
- Substitution
Volume 2 = 12 x 3 / 3.25
- Simplification
Volume 2 = 36 / 3.25
- Result
Volume 2 = 11 L