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Gekata [30.6K]
3 years ago
15

What happens to the air particles in the bubble when you pull up on the plunger

Chemistry
1 answer:
victus00 [196]3 years ago
7 0

The air particles in the bubble are forced to expand when we pull up on the plunger.

<h3><u>Explanation:</u></h3>

Pulling creates a large amount of volume , when the volume of the air bubble is increased, air particles inside the bubble tries to accumulate all of the volume by expanding the size of the bubble. Since according to Ideal gas law,

P V = n R T

where P = Pressure of the gas

V = Volume of the gas

n = No. of moles

R = Boltzmann's constant

T = Temperature

We can observe that pressure is inversely proportional to the volume of the gas. Therefore, when we pull up the plunger, the volume of the air bubble is increased and the pressure inside it is decreased.

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How many grams od Mg(OH)2 will be needed to neutralize 25 mlod
irina [24]

Answer:

0.0073 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For HCl :

Molarity = 0.010 M

Volume = 25 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 25×10⁻³ L

Thus, moles of HCl :

Moles=0.010 \times {25\times 10^{-3}}\ moles

Moles of HCl  = 0.00025 moles

Considering the reaction shown below as:-

2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O

2 moles of HCl reacts with 1 mole of Mg(OH)_2

So,

1 moles of HCl reacts with 1/2 mole of Mg(OH)_2

Also,

0.00025 moles of HCl reacts with \frac{1}{2}\times 0.00025 mole of Mg(OH)_2

Mole of Mg(OH)_2 = 0.000125 moles

Molar mass of Mg(OH)_2 = 58.3197 g/mol

Mass = Moles*Molar mass = 0.000125\times 58.3197\ g = 0.0073 g

5 0
3 years ago
Read 2 more answers
When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0
4 years ago
Answer fast and I’ll give BRAINLIEST please and thank you!! IT WOULD HELP ALOT IF U DONT RUSH AND ANSWER CORRECTLY
andrezito [222]

Answer:

i am thinking that they will be extinct

Explanation:

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3 0
4 years ago
PLEASE HELP
lozanna [386]

Answer:

The Answer is A

Explanation:

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5 0
3 years ago
The maximum number of electrons that are possible at a given energy level depends on the number of ____ at the energy level.
VMariaS [17]

Answer:

  • <u><em>     orbitals      </em></u>

Explanation:

Each orbital may contain a maximum of two electrons.

The energy level is the principal quantum number: 1, 2, 3, 4, 5, 6, 7.

The principal quantum number limits the kind of orbital (ℓ ) and the number of orbitals (mℓ ).

I. Principal quantum number, n = 1

  Angular or orbital quantum number : ℓ = 0 ⇒ ortibal s

  Magnetic quantum number:  mℓ = 0

                                 ⇒ number of orbitals 1 ⇒ number of electrons: 2

                         

II. Principal quantun number, n = 2

  Angular or orbital quantum number : ℓ = 0 and 1 ⇒ ortibal s and p

  Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                 ⇒ number of orbitals 4 ⇒ number of electrons: 8

III. Principal quantun number, n = 3

    Angular or orbital quantum number : ℓ = 0, 1, and 2 ⇒ ortibal s, p and d

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                 ⇒ number of orbitals 9 ⇒ number of electrons: 18

IV. Principal quantun number, n = 4

    Angular or orbital quantum number : ℓ = 0, 1, 2, and 3 ⇒ ortibal s, p, d and f

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                            for ℓ = 3: mℓ = ±3, ±2, ±1, and 0: 7 f ortitals

                                 ⇒ number of orbitals 16 ⇒ number of electrons: 32.

Thus, you have:

energy level, n    maximum number of     maximum number of

                             orbitals                           electrons

      1                           1                                      2

      2                          4                                     8

      3                          9                                    18

      4                          16                                   32

Those numbers follow a rule: n² and 2n². You can verify that the previous numbers are in accordance with those formulas.

3 0
4 years ago
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