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trapecia [35]
3 years ago
7

Photochemical isomerization of (E,E)-2,4-hexadiene to (Z,E)-2,4-hexadiene is a two-step process in which a photochemically drive

n intermediate forms and then thermally rearranges to give the product. Draw the structure of this intermediate, using wedge-and-dash bonds to denote the appropriate stereochemistry.
Chemistry
1 answer:
Lisa [10]3 years ago
8 0

Answer:

Its response to this question is as follows:

Explanation:

Please find in the attachment file the complete query and the answer file.

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What distance will a travel 65km/hr in 3.0 hrs?
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Sodium explodes when it contacts water. If I have a compound that contains sodium, will it explode if it is exposed to water?
Vaselesa [24]

Answer:

Option D = No, when elements combine to form a new material, they have properties unique to the new materials.

Explanation:

When sodium contact with water it loses its one electron and thus gain positive charge. When there are more sodium atoms present and many atoms do this thus more positive ions are produced and these positive ions repeal each other at high speed and explosion occur.

But when it form compound with other material, it will not showed this behavior.

Example:

Consider the sodium chloride, when it dissolve in water sodium not showed explosion. In sodium chloride sodium already gives its electron to the chlorine and have stable electronic configuration. The sodium present in cationic form. When it dissolve, partial positive charge of water surrounds the Cl⁻ and partial negative charge of water surrounds the Na⁺ ion, ans sodium chloride gets dissolve into water without explosion.

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3 years ago
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As shown in table 15.2, kp for the equilibrium n21g2 + 3 h21g2 δ 2 nh31g2 is 4.51 * 10-5 at 450 °c. for each of the mixtures lis
Setler79 [48]
Our reaction balanced equation at equilibrium N2(g) + 3 H2(g) ↔ 2 NH3(g)
and we have the Kp value at equilibrium = 4.51 X 10^-5
A) 98 atm NH3, 45 atm N2, 55 atm H2

when Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
                = 98^2 / (45 * 55^3) = 1.28 x 10^-3
by comparing the Kp by the Kp at equilibrium(the given value) So,
Kp > Kp equ So the mixture is not equilibrium,
 it will shift leftward (to decrease its value) towards the reactants to achieve equilibrium.
B) 57 atm NH3, 143 atm N2, no H2
∴ Kp = [P(NH3)]^2 / [P(N2)]
         = 57^2 / 143 = 22.7
∴Kp> Kp equ (the given value) 
∴it will shift leftward (to decrease its value) towards reactants to achieve equilibrium.

c) 13 atm NH3, 27 atm N2, 82 atm H2
∴Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
       =  13^2 / (27* 82^3) = 1.14 X 10^-5
∴ Kp< Kp equ (the given value)
∴it will shift rightward (to increase its value) towards porducts to achieve equilibrium.


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How are sea slugs able to make their own food like green algae?
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