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3 years ago

What is the frequency of green light that has a wavelength of 5.14 x 10^-7m?

Chemistry

1 answer:

nata0808 [166]3 years ago

5 0

Answer:

Frecuency = 5,83x10⁻⁷ Hz

Explanation:

The equation that connects wavelenght and frequency is given by:

λ = c/ν

λ=wavelenght (expressed in lenght´s units)

c= speed of light (3x10⁸ m/sec)

ν=frequency (expressed in units of time⁻¹ or Herzt)

In our case, λ=5,14x10⁻⁷ m , so replacing in our previous formula, this gives us the final result of ν (frequency for green light) of 5,83x10¹⁴ Hz (or Herzt)

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What does polar and nonpolar mean in science

MissTica

Polar molecules are molecules are essentially have no molecular symmetry.

Nonpolar molecules are molecules that have molecular symmetry.

Water is a very basic example of a polar molecule.

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3 years ago

Read 2 more answers

Provide the IUPAC names for

ollegr [7]

Answer:

For a: The IUPAC name of the compound is N-ethylethaneamide.

For b: The IUPAC name of the compound is N,N-diethylmethaneamide.

For c: The IUPAC name of the compound is ethyl pentanoate

Explanation:

To name a compound, first look for the longest possible carbon chain.

For a:

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is $R-CO-NH_2$ , where R is an alkyl or aryl group.

In part (a), the alkyl group has 2 carbon atoms and thus, the prefix used is 'eth-'

Also, an ethyl substituent is directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N-ethylethaneamide.

For b:

Amide group is a type of functional group where an amine group is attached to a carbonyl group. The general formula of amide is $R-CO-NH_2$ , where R is an alkyl or aryl group.

In part (b), the alkyl group has 1 carbon atoms and thus, the prefix used is 'meth-'

Also, two ethyl substituents are directly attached to N-atom. It is an alkane structured hydrocarbon thus, the suffix used will be '-ane'

Hence, the IUPAC name of the compound is N,N-diethylmethaneamide.

For c:

Esters are a kind of organic molecules having functional groups, $R-COO-R'$ where R and R' are the alkyl or aryl groups. They are formed by the combination of alcohol and carboxylic acid.

These functional group compounds are named in two words which is alkyl alkanoates, where alkyl refers to the alcoholic part and alkanoate refers to the carboxylic acid part of the molecule. The numbering of the parent chain in esters is done from the carboxylic carbon. The alkyl part is not given any numbers.

In part (c), there are 5 carbon atoms present in a straight chain and thus, the prefix used is 'pent-'

Also, an ethyl group forms the alcoholic part.

Hence, the IUPAC name of the compound is ethyl pentanoate

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3 years ago

Which of the following item(s) explain the differences between the Ka values. Choose one or more: A. The oxidation state for oxy

Allisa [31]

Answer:

C. The electron-withdrawing fluorine atoms pull electron density from the oxygen in trifluoroacetate. The negative charge is more stabilized in trifluoroacetate by this effect.

Explanation:

The structures of trifluoroacetate and acetic acid are both shown in the image attached.

The trifluoroacetate anion (CF3CO2-), just like the acetate anion has in the middle, two oxygen atoms.

However, in the trifluoroacetate anion, there are also three electronegative fluorine atoms attached to the nearby carbon atom attached to the carbonyl, and these pull some electron density through the sigma bonding network away from the oxygen atoms, thereby spreading out the negative charge further. This effect, called the "inductive effect" stabilizes the anion formed,the trifouoroacetate anion is thus more stabilized than the acetate anion.

Hence, trifluoroacetic acid is a stronger acid than acetic acid, having a pKa of -0.18.

Hope this helps!

Please mark brainliest!

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3 years ago

How many lead (Pb) atoms are in a 5.32 g sample of pure lead?

Elanso [62]

Answer:

1.55×10²² molecules.

Explanation:

We'll begin by calculating the number of mole in 5.32 g of pure lead (Pb). This can be obtained as follow:

Mass of Pb = 5.32 g

Molar mass of Pb = 207 g/mol

Mole of Pb =?

Mole = mass /molar mass

Mole of Pb = 5.32/207

Mole of Pb = 0.0257 mole

Finally, we shall determine the number of molecules in 0.0257 mole of Pb. This can be obtained as follow:

From Avogadro's hypothesis,

I mole of Pb contains 6.02×10²³ molecules.

Therefore, 0.0257 mole will contain = 0.0257 × 6.02×10²³ = 1.55×10²² molecules.

Therefore, 5.32 g of pure lead (Pb) contains 1.55×10²² molecules.

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3 years ago

Does anyone have the student exploration sheet answers for the Drug Dosage (Forensic Science) Gizmos lab?

Novay_Z [31]

Answer:

sorry neither me ..........

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