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2 years ago

All weather is energy in motion. Where does the energy come from

Chemistry

2 answers:

alekssr [168]2 years ago

8 0

Answer:

The Sun radiates huge amounts of energy. Only a small portion of that energy hits the Earth, but it is enough to light our days, heat our air and land, and create weather systems over the oceans. Most of the energy you will learn about comes from the Sun. The Earth also gives off energy.

Explanation:

expeople1 [14]2 years ago

3 0

Answer:

"The Sun radiates huge amounts of energy. Only a small portion of that energy hits the Earth, but it is enough to light our days, heat our air and land, and create weather systems over the oceans. Most of the energy you will learn about comes from the Sun. The Earth also gives off energy."

By the way I got this off thee internet and copy and pasted it so don't write it just look and write in your own words please. Please do not copy and paste or write what i wrote because this is someone else's explanation or answer

Hope this helps!! Also please rank thank you.

Explanation:

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How many molecules are there in 2.30g of NH3

Vinil7 [7]

Answer:

8.13x10^22 molecules

Explanation:

We can use the Avogadro's number(6.022 x 10^23 units / mole)

2.30 g NH3 (1 mol / 17.03 g ) (6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

Hope this helps! Feel free to ask any questions!

6 0

2 years ago

Draw the structures of all monobromo derivatives of pentane, c5h11br, which contain a 4-carbon chain.

SVETLANKA909090 [29]

Two or more compounds that have same molecular formula but differ in the arrangement of atoms in molecule and thus posses different properties are known as isomers.

The molecular formula of pentane is $C_5H_1_2$ substituting one hydrogen from pentane with bromine results in the formation of monobromo derivatives of pentane having molecular formula, $C_5H_1_1Br$ .

The structure of monobromo derivatives of pentane that is 1-bromopentane, 2-bromopentane, and 3-bromopentane and having molecular formula, $C_5H_1_1Br$ is shown in the image.

The other two arrangements of monobromo derivatives of pentane that is 2-bromo-2-methylbutane and 2-bromo-3-methylbutane is shown in the image.

There are different structures of monobromo derivatives of pentane having molecular formula, $C_5H_1_1Br$ which contain a 4-carbon chain are 1- bromo-2-methylbutane and 1-bromo-3-methylbutane shown in the image.

5 0

3 years ago

what is the chemical reaction and mole ratio between oxalate and permanganate in the titration reaction

Tom [10]

5C2O4^(2-)(aq) + 2MnO4^-(aq) + 16H+(aq) → 10CO2(g) + 2Mn2+(aq) + 8H2O(l)` is the chemical reaction and mole ratio between oxalate and permanganate in the titration reaction.

A chemical reaction is a procedure that causes one group of chemical components to change chemically into another. Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that only affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei (no change to the elements present). The study of chemical processes involving unstable and radioactive elements, where both electronic and nuclear changes may take place, is known as nuclear chemistry.

To know more about chemical reaction, click here,

brainly.com/question/11231920

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6 0

1 year ago

Which of the following is true about technology and science

galben [10]

Answer:

car

Explanation:

4 0

3 years ago

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =

Lady bird [3.3K]

Answer:

$4.86\times10^{-7}\ \text{m}$

Explanation:

R = Rydberg constant = $1.09677583\times 10^7\ \text{m}^{-1}$

$n_1$ = Principal quantum number of an energy level = 2

$n_2$ = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

$\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}$

The wavelength of the light emitted is $4.86\times10^{-7}\ \text{m}$ .

6 0

3 years ago