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Olegator [25]
3 years ago
10

How many grams of lithium fluoride is required to make 1.2 L of a 3.5 M solution?

Chemistry
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

109.2g

Explanation:

First, let us obtain the number of mole of lithium fluoride in the solution. This is illustrated below:

Molarity of lithium fluoride (LiF) = 3.5M

Volume = 1.2L

Number of mole of LiF =?

Molarity = mole/Volume

Mole = Molarity x Volume

Number of mole LiF = 3.5 x 1.2

Number of mole LiF = 4.2 moles

Now let us convert 4.2 moles to grams in order to obtain the desired result. This illustrated below:

Molar Mass of LiF = 7 + 19 = 26g/mol

Number of mole of LiF = 4.2 moles

Mass of LiF =?

Mass = number of mole x molar Mass

Mass of LiF = 4.2 x 26

Mass of LiF = 109.2g

Therefore, 109.2g of lithium fluoride is required.

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Explanation:

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2 years ago
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What is the density of motor oil in g/mL if 1.25 quart (qt) weighs 2.25 pounds (lb)?
Doss [256]

Answer:

0.86 g/mL

Explanation:

In order to solve the problem, you have to know the formula for "Density." Density refers to<em> </em><em>"mass per unit volume." </em><em>It's formula is:</em>

  • <em>Density (ρ) = </em>\frac{mass}{Volume}<em />

Next, we have to convert the units of measurement in accordance to what is being asked in the problem. It is asking for "g/mL," which means we have to convert 1.25 quarts<em> (qt.) </em>to mL and 2.25 pounds<em> (lbs.)</em> to grams.

Let's solve.

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1.25 qt. x \frac{946.35 mL}{1 qt.} =<em> 1,182.94 mL</em>

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2.25 pounds x \frac{453.592 grams}{1 pound} = <em>1,020.58 grams</em>

Now that we converted them to their appropriate units of measurement, we can now solve for density.

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<em>The density of the motor oil is 0.86 g/mL</em>

5 0
3 years ago
1. Fluorine-21 has a half-life of approximately 5 seconds. How much of a 200 gram sample would remain after 1 minute.
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Answer:

Fluorine-21 has a half-life of approximately 5 seconds. How much of a 200 gram sample would remain after 1 minute.

1/4096

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3 years ago
What is the percent composition of a copper chloride compound if a 269 g sample contains 127 g of copper and 142 grams of chlori
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Answer:

Explanation:

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5 0
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