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Olegator [25]
3 years ago
10

How many grams of lithium fluoride is required to make 1.2 L of a 3.5 M solution?

Chemistry
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

109.2g

Explanation:

First, let us obtain the number of mole of lithium fluoride in the solution. This is illustrated below:

Molarity of lithium fluoride (LiF) = 3.5M

Volume = 1.2L

Number of mole of LiF =?

Molarity = mole/Volume

Mole = Molarity x Volume

Number of mole LiF = 3.5 x 1.2

Number of mole LiF = 4.2 moles

Now let us convert 4.2 moles to grams in order to obtain the desired result. This illustrated below:

Molar Mass of LiF = 7 + 19 = 26g/mol

Number of mole of LiF = 4.2 moles

Mass of LiF =?

Mass = number of mole x molar Mass

Mass of LiF = 4.2 x 26

Mass of LiF = 109.2g

Therefore, 109.2g of lithium fluoride is required.

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How many solutions does the equation (3x + 7) = -4 have?<br>B. one<br>C. WO<br>D. infinitely many​
Eddi Din [679]

Answer:

Its One

Explanation:

hope it helps!

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8 0
4 years ago
Pleaaaaase helppppppppppppp ASAP
laiz [17]

Answer:

Explanation:

a) The forward reaction is exothermic, hence when temperature is increased the equilibrium shift towards the reactants side to get rid of the excess energy. This will mean that more reactants are produced decreasing yield

b) There are a fewer number of moles of gas on the right side compared to the left side (Just count the coefficients before each compound) so a higher pressure will mean that the equilibrium will shift towards the products side in order to decrease the pressure. This will mean that more products are formed increasing yield

c) When something is powdered it's surface area to volume ratio increases. A higher surface area means that the particles around it have more area to work on so the frequency of collisions will increase increasing the rate of reaction. This is why iron is powdered.

4 0
3 years ago
Consider the reaction below. Initially the concentration of SO2Cl2 is 0.1000 M. Solve for the equilibrium concentration of SO2Cl
tensa zangetsu [6.8K]

Answer:

[SO_2Cl_2] = 0.09983 M

Explanation:

Write the balance chemical equation ,

SO_2Cl_2((g) = SO_2(g) + Cl_2(g)

initial concenration of SO_2Cl_2((g)  =0.1M

lets assume that degree of dissociation=\alpha

concenration of each component at equilibrium:

[SO_2Cl_2] = 0.1-0.1\alpha

[SO_2] = 0.1\alpha

[Cl_2] = 0.1\alpha

Kc =\frac{0.1\alpha \times 0.1\alpha}{0.1-0.1\alpha}

Kc =\frac{0.1\alpha \times \alpha}{1-\alpha}

as \alpha is very small then we can neglect  1-\alpha

therefore ,

Kc ={0.1\alpha \times \alpha}

\alpha =\sqrt{\frac{Kc}{0.1}}

\alpha = 1.73 \times 10^{-3}

Eqilibrium concenration of [SO_2Cl_2] = 0.1-0.1\alpha = 0.1-0.1\times 0.00173

[SO_2Cl_2] = 0.09983 M

4 0
3 years ago
Give the number of lone pairs around the central atom and the geometry of the ion IBr2.
Salsk061 [2.6K]

Answer:

Option E!

Explanation:

If we were to draw the lewis dot structure for IBr2 -, we would first count the total number of valence electrons ( " available electrons " ). Iodine has 7 valence electrons, and so does Bromine, but as Bromine exists in 2, the total number of valence electrons would be demonstrated below;

7 + 7 * ( 2 ) =\\7 + 14 + 1 =\\22 Electrons

Don't forget the negative on the Bromine!

Now go through the procedure below;

1 ) Place Iodine in the middle and draw single bonds to each of the bromine.

2 ) Add three lone pairs on each of the Bromine's

3 ) Now we have 6 electrons left, if we were to exclude the electrons shared in the " single bonds. " This can be placed as three lone pairs on Iodine ( central atom )!

The molecular geometry can't be linear, as there are lone pairs on the atoms. This makes it bent.

4 0
3 years ago
What is the percent by mass of 54.7g of calcium chloride dissolved in 500g of water?
Advocard [28]
% by mass = (mass solute/mass solution)*100%
mass  of the solute = 54.7 g
mass of the solution = mass solute + mass solvent=54.7+500=554.7 g
% by mass = (54.7/554.7)*100%≈0.0986*100% = 9.86%

3 0
4 years ago
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