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Ivanshal [37]
3 years ago
15

What is the Vertex for #17? The axis of symmetry for #18?

Mathematics
1 answer:
Darya [45]3 years ago
5 0
The vertex for #17 is at 1,1 and the axis of symmetry is at -1 on the X line.i hope this helps.
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mars1129 [50]

Answer:

The inquality is always false i think..

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20-%203%20%2B%205i%20%20%5Cdiv%20%20-%203%20-%204i" id="TexFormula1" title=" - 3 + 5i \div
Likurg_2 [28]

Answer:

\frac{-11}{25}+\frac{-27}{25}i given you are asked to simplify

\frac{-3+5i}{-3-4i}

Step-by-step explanation:

You have to multiply the numerator and denominator by the denominator's conjugate.

The conjugate of a+bi is a-bi.

When you multiply conjugates, you just have to multiply first and last.

(a+bi)(a-bi)

a^2-abi+abi-b^2i^2

a^2+0         -b^2(-1)

a^2+-b^2(-1)

a^2+b^2

See no need to use the whole foil method; the middle terms cancel.

So we are multiplying top and bottom of your fraction by (-3+4i):

\frac{-3+5i}{-3-4i} \cdot \frac{-3+4i}{-3+4i}=\frac{(-3+5i)(-3-4i)}{(-3-4i)(-3+4i)}

So you will have to use the complete foil method for the numerator. Let's do that:

(-3+5i)(-3+4i)

First: (-3)(-3)=9

Outer::  (-3)(4i)=-12i

Inner: (5i)(-3)=-15i

Last: (5i)(4i)=20i^2=20(-1)=-20

--------------------------------------------Combine like terms:

9-20-12i-15i

Simplify:

-11-27i

Now the bottom (-3-4i)(-3+4i):

F(OI)L (we are skipping OI)

First:-3(-3)=9

Last: -4i(4i)=-16i^2=-16(-1)=16

---------------------------------------------Combine like terms:

9+16=25

So our answer is \frac{-11-27i}{25}{/tex] unless you want to seprate the fraction too:[tex]\frac{-11}{25}+\frac{-27}{25}i

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Answer:

23

Step-by-step explanation:


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She would have spent $600 on the furniture, and $200 on the T.V.

Her original savings were $800.
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List the first 10 triangular numbers
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