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3 years ago

What is 152.925 rounded to the nearest hundredth

Mathematics

2 answers:

Mandarinka [93]3 years ago

4 0

The answer rounded to the nearest hundredth is 152.93

timofeeve [1]3 years ago

4 0

152.925 rounded to the nearest hundredth is 152.93.

Solution:

To round to the nearest hundredth, first we have to locate the hundredths place. And the we have to follow the general rounding off rules given below,

General rounding off rules:

First look at the digit to immediate right of rounding off digit

If that digit is less than 5, do not change the rounding digit but drop all digits to the right of it.

If that digit is greater than or equal to five, add one to the rounding digit and drop all digits to the right of it.

The given number is 152.925. Here, the digit to immediate right of rounding off digit is 5 so, we have to add one to the rounding digit and drop all digits to the right of it

i.e, $2+1=3$ Therefore, the value will be $152.93$

As per the rules, rounding to the nearest 0.01 or the Hundredths Place value will be 152.93.

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Answer:

The calculated chi -square value =5.7356 Is less than12.01 at 0.1level of significance .

The null hypothesis is accepted.

The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Step-by-step explanation:

Step:-(1)

Given data 28 25 29 25 32 36 27 24

Sample size 'n' = 8

mean of the sample (x⁻) = ∑x /n = $\frac{28+ 25+ 29 +25 +32 +36 + 27 + 24}{8}$

mean of the sample (x⁻) = 28.25

x x- x⁻ (x-x⁻ )²

28 28 - 28.25 = -0.25 0.0625

25 25 -28.25 = -3.25 10.56

29 29-28.25 = 0.75 0.5625

25 25-28.25 = -3.25 10.56

32 32-28.25 = 3.75 14.06

36 36-28.25 = 7.75 60.06

27 27-28.25 = -1.25 1.5625

24 24-28.25 = -4.25 18.06

∑(x-x⁻)² = 115.4875

Step:-(2)

The sample standard deviation

S² = ∑(x-x⁻)²/n-1 = $\frac{115.4875 }{7}$ = 16.49

By using χ² distribution

χ² = $\frac{ns^2 }{variance}$

By above test can be applied only if the population from which sample is drawn normal.

Given data For the past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Population variance σ² = 23

Step:-(3)

Null hypothesis :H₀:σ² = 23

Alternative hypothesis :H₁:≠23

$X^{2} = \frac{8 (16.49)}{23}=5.7356$