When the specific heat capacity of the water is 4.18 J/g.°C so, we are going to use this formula to get the heat for cooling three phases changes from steam to liquid and from liquid to ice (solid) :
when Q = M*C*ΔT
Q is the heat in J
and M is the mass in gram = 1 mol H2O * 18 g/mol(molar mass) = 18 g
C is the specific heat J/g.°C
ΔT is the change in temperature
Q = Mw *[ ( Csteam * ΔTsteam)+(Cw*ΔTw) + (Cice * ΔT ice)]
= 18 g * [(2.01 * (155-100°C)) + (4.18 * (100-0°C)) + (2.09 * (0 - 55 °C))]
∴Q = 7444.8 J
and when we know that the heat of fusion for water = 334J/g
and heat of vaporization for water = 2260J/g
∴Q for the two phases changes = M * (2260+334)
= 18 * (2260+334)
= 46692 J
∴ Q total = 7444.8 + 46692 = 54136.8 J
Soil temperature and <span>water content</span>
Answer:
a)
,
, b)
, 
Explanation:
a) The ideal gas is experimenting an isocoric process and the following relationship is used:

Final temperature is cleared from this expression:


The number of moles of the ideal gas is:



The final temperature is:


The final pressure is:



b) The ideal gas is experimenting an isobaric process and the following relationship is used:

Final temperature is cleared from this expression:




The final volume is:



Answer: so the answer is A
Explanation: The relationship between an object's mass (m), its acceleration (a), and the applied force (f) is F=ma. ... This law requires that the direction of the acceleration vector is in the same direction as the force vectors.
Answer:
C. oxygen atom
Explanation:
H2O contains two hydrogen atoms and one oxygen atom.