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NeX [460]
3 years ago
7

A mothball, composed of naphthalene (c10h8), has a mass of 1.64 g . part a how many naphthalene molecules does it contain?

Chemistry
1 answer:
yulyashka [42]3 years ago
6 0
Answer is: 7,5·10²¹ <span>naphthalene molecules.
</span>m(C₁₀H₈) = 1,64 g.
n(C₁₀H₈) = m(C₁₀H₈) ÷ M(C₁₀H₈).
n(C₁₀H₈) = 1,64 g ÷ 128,17 g/mol.
n(C₁₀H₈) = 0,0125 mol.
N(C₁₀H₈) = n(C₁₀H₈) · Na.
N(C₁₀H₈) = 0,0125 mol · 6,022·10²³ 1/mol.
N(C₁₀H₈) = 7,5·10²¹.
Na - Avogadro number.

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Hydrogen and oxygen react chemically to form water how much water would form if 14.8grams of hydrogen reacted with 34.8 grams of
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Answer:

There will be formed 39.1935 grams H2O formed

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<u>Step 1:</u> The balanced equation

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<u>Step 2</u>: Given data

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Molar mass of hydrogen = 2.02 g/mole

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Molar mass of oxygen = 32 g/mole

<u>Step 3: </u>Calculate moles

moles = mass / Molar mass

moles of hydrogen = 14.8g/ 2.02 g/mole = 7.33 moles

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For 2 moles hydrogen consumed, we need 1 mole of oxygen.

This means oxygen is the limiting reagens and will be consumed completely. Hydrogen is the reactant in excess, there will remain 5.155 moles of hydrogen

<u>Step 4:</u> Calculate moles of H2O

We see that for 2 moles of H2 consumed, there is needed 1 mole of O2, to produce 2 moles of H2O.

For 1.0875 moles of oxygen consumed, there will be produced 2.175 moles of H2O

<u>Step 5:</u> Calculate mass of water

Mass of H2O = moles of H2O * Molar mass of H2O

Mass of H2O = 2.175 moles * 18.02 g/moles 39.1935 grams

There will be formed 39.1935 grams H2O formed

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