Please select the word from the list that best fits the definition Composed of one type of compound molecule compound mixture ch
1 answer:
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So let's convert this amount of mL to grams:
Then we need to convert to moles using the molar weight found on the periodic table for mercury (Hg):
Then we need to convert moles to atoms using Avogadro's number:
So now we know that in 1.2 mL of liquid mercury, there are present.
Taking into account the reaction stoichiometry, P₄ will be the limiting reagent.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
8 P₄ + 3 S₈ → 8 P₄S₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- P₄: 8 moles
- S₈: 3 moles
- P₄S₃: 8 moles
The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
<h3>Limiting reagent in this case</h3>To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?
<u><em>moles of P₄= 10.667 moles</em></u>
But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.
Learn more about the reaction stoichiometry:
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A) At pH=1
This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)
The chemical structure for CH₃COOH is the first one in the attached images.
B) At pH=7
This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)
The chemical structure for CH₃COO⁻ is the second one in the attached images.
Have a nice day!
A) At pH=1
This pH is lower than the value for the pKa, so Acetic acid wouldn't be ionized, but the equilibrium would be displaced to CH₃COOH
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the left)
The chemical structure for CH₃COOH is the first one in the attached images.
B) At pH=7
This pH is higher than the value for the pKa, so Acetic acid would be ionized, and the equilibrium would be displaced to CH₃COO⁻
CH₃COOH ⇄ CH₃COO⁻ + H₃O⁺ (equilibrium displaced to the right)
The chemical structure for CH₃COO⁻ is the second one in the attached images.
Have a nice day!