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WINSTONCH [101]
3 years ago
10

Mention the various ways by which soluble and insoluble salts are prepared

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

Explanation:

soluble and insoluble salts are prepared by processes like neutralization reactions, simple displacement reactions and double displacement reactions.

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A few Critical Thinking questions/creativity on the topic 'Particles of matter are very small'
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Answer:

Any substance which occupies space and has mass is known as matter. States of matter: Matter exist in three different states that are Solid, Liquid and Gas. Matter is made up of very small particles

Explanation:

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3 years ago
A container was found in the home of the victim that contained 130 g of ethylene glycol in 380 g of liquid. What was the percent
Kaylis [27]

Answer:

34.21%

Explanation:

Given parameters:

Mass of ethylene glycol in the container = 130g

Mass of the liquid in total = 380g

Unkown:

Percentage of ethylene glycol in the liquid =?

Solution

To find the percentage of the ethylene glycol in liquid, we use the expression below:

Percentage of ethylene glycol in liquid = \frac{mass of ethylene glycol}{mass of liquid} x 100

Percentage of ethylene glycol = \frac{130}{380} x 100

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7 0
3 years ago
Data Collection
vladimir2022 [97]

<u>Answer:</u>

<u>For a):</u> The mass percent of naphthalene in the original sample is 31.00 %.

<u>For b):</u> The mass percent of 3-nitroaniline in the original sample is 32.03 %.

<u>For c):</u> The mass percent of benzoic acid in the original sample is 29.97 %.

<u>For d):</u> The total percent recovered is 93.00 %.

<u>Explanation:</u>

Percentage by mass is defined as the ratio of the mass of a substance to the mass of the solution multiplied by 100. The formula used for this is:  

\text{Percent by mass}=\frac{\text{Mass of substance}}{\text{Mass of a solution}} \times 100               ......(1)

a):

Mass of naphthalene = 0.483 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of naphthalene}=\frac{0.483 g}{1.558}\times 100\\\\\%\text{ mass of naphthalene}=31.00 \%

b):

Mass of 3-nitroaniline = 0.499 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of 3-nitroaniline}=\frac{0.499 g}{1.558}\times 100\\\\\%\text{ mass of 3-nitroaniline}=32.03 \%

c):

Mass of benzoic acid = 0.467 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\%\text{ mass of benzoic acid}=\frac{0.467 g}{1.558}\times 100\\\\\%\text{ mass of benozic acid}=29.97 \%

d):

Total mass recovered = [0.483 + 0.499 + 0.467] = 1.449 g

Mass of the sample = 1.558 g

Plugging values in equation 1:

\text{Total percent recovered}=\frac{1.449 g}{1.558}\times 100\\\\\text{Total percent recovered}=93.00\%

8 0
3 years ago
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