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Sergio039 [100]

3 years ago

13

What causes the moon to be illuminated?

1 answer:

I am Lyosha [343]3 years ago

5 0

Answer:

Reflection

Explanation:

The light from Earth's surface, reflected back towards the Moon, can illuminate it all the same. This is why, when the Moon is in a crescent phase, you can still see features on the dark portion of the Moon: we call this reflected, illuminating light the phenomenon of Earthshine.

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Which of the following is an ozone depleting substance (ODS)?

pantera1 [17]

Answer:

your answer is b. chlorofluorocarbon(CFC

Explanation:

hope it is helpful to you

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5 0

4 years ago

Read 2 more answers

If it takes 645 J of energy to warm a 5.51-g sample of water, how much energy would be required to warm 55.1 g of water by the s

hjlf

Answer:

Explanation:If 5.51 g of water needs 645 J of energy to warm then 55.1 g of water needs 6450 J of energy to warm.

4 0

4 years ago

Which of the following is not a property of typical solids?

Orlov [11]

I believe that it's C: Easily compressible

3 0

3 years ago

7. A square chunk of plastic has a length of 5 cm, width of 5 cm and height of 5 cm. It has a mass of 200 g. What is its density

BaLLatris [955]

Answer:

$d=1.6\ g/cm^3$

Explanation:

Given that,

The dimension of a square chunk of plastic is 5 cm × 5 cm × 5 cm

Mass, m = 200 g

We need to find its density

Density = mass/volume

It will form a cube. It volume = side³

So,

$d=\dfrac{200\ g}{5^3\ cm^3}\\\\d=1.6\ g/cm^3$

Hence density is $1.6\ g/cm^3$

5 0

4 years ago

A red sports drink contains Red 40 dye. A 5.4 mL aliquot of this sports drink was diluted to 25.0 mL with deionized water in a v

miskamm [114]

Answer:

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

Explanation:

Concentration of red dye in sport drink before dilution $C_1=?$

Volume of the sport drink before dilution $V_1=5.4 mL$

Concentration of red dye in sport drink after dilution $C_2=18.1 ppm$

Volume of the sport drink after dilution $V_2=25.0 mL$

$C_1V_1=C_2V_2$ ( dilution )

$C_1=\frac{C_2V_2}{V_1}=\frac{18.1 ppm\times 25.0 mL}{5.4 mL}$

$C_1=83.80 ppm\approx 84.0ppm$

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

6 0

3 years ago