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2 years ago

Need some help with this Chem Question :)

Chemistry

1 answer:

Kruka [31]2 years ago

5 0

Answer:

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Explanation:

The activity series helps us to easily define whether or not a reaction will occur.

Elements at the top of the activity series are highly reactive and will always displace those at the bottom of the series in any reaction.

With the above information in mind, let us answer the questions given above.

Ag + NaNO₃ —> Na + AgNO₃

The above reaction will not occur because Na is higher than Ag in the activity series. Thus, Ag cannot displace Na from solution.

Pb + Mg(NO₃)₂ —> Pb(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Pb in the activity series. Thus, Pb cannot displace Mg from solution.

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

The above reaction will occur because Mg is higher than Fe in the activity series. Thus, Mg will displace Fe from solution.

Cu + Mg(NO₃)₂ —> Cu(NO₃)₂ + Mg

The above reaction will not occur because Mg is higher than Cu in the activity series. Thus, Cu cannot displace Mg from solution.

From the above illustration, only

Mg + Fe(NO₃)₂ —> Fe + Mg(NO₃)₂

Will occur.

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alukav5142 [94]

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3 years ago

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3 years ago

A 60.0 g block of iron that has an initial temperature of 250. °C and 60.0 g bloc of gold that has an initial temperature of 45.

Maslowich

Answer:

The final temperature at the equilibrium is 204.6 °C

Explanation:

Step 1: Data given

Mass of iron = 60.0 grams

Initial temperature = 250 °C

Mass of gold = 60.0 grams

Initial temperature of gold = 45.0 °C

The specific heat capacity of iron = 0.449 J/g•°C

The specific heat capacity of gold = 0.128 J/g•°C.

Step 2: Calculate the final temperature at the equilibrium

Heat lost = Heat gained

Qlost = -Qgained

Qiron = -Qgold

Q=m*c*ΔT

m(iron) * c(iron) *ΔT(iron) = -m(gold) * c(gold) *ΔT(gold)

⇒with m(iron) = the mass of iron = 60.0 grams

⇒with c(iron) = the specific heat of iron = 0.449 J/g°C

⇒with ΔT(iron)= the change of temperature of iron = T2 - T1 = T2 - 250.0°C

⇒with m(gold) = the mass of gold= 60.0 grams

⇒with c(gold) = the specific heat of gold = 0.128 J/g°C

⇒with ΔT(gold) = the change of temperature of gold = T2 - 45.0 °C

60.0 *0.449 * (T2 - 250.0) = -60.0 * 0.128 * (T2 - 45.0 )

26.94 * (T2 - 250.0) = -7.68 * (T2 - 45.0)

26.94T2 - 6735 = -7.68T2 + 345.6

34.62T2 = 7080.6

T2 = 204.5 °C

The final temperature at the equilibrium is 204.6 °C

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3 years ago

Compare and contrast alpha beta and gamma radiation

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Penetrative power
Range in air

Ionising ability
Alpha radiation has strong ionising ability, while beta only has moderate ionisation and gamma is very weakly ionising.

Penetrative power
Alpha particles are weakly penetrating, stopped by paper, while beta particles have stronger penetrating ability, stopped by skin and gamma radiation is very strongly penetrating, stopped only by thick layers of lead.

Range in air
Alpha particles- range of only a few centimetres
Beta - range of up to one meter
Gamma- infinite range in air.

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3 years ago

If a sample of sodium chloride with a mass of

alex41 [277]

Original molarity was 1.7 moles of NaCl

Final molarity was 0.36 moles of NaCl

Given Information:

Original (concentrated) solution: 25 g NaCl in a 250 mL solution, solve for molarity

Final (diluted) solution: More water is added to make the new total volume 1.2 liters, solve for the new molarity

1. Solve for the molarity of the original (concentrated) solution.

Molarity (M) = moles of solute (mol) / liters of solution (L)

Convert the given information to the appropriate units before plugging in and solving for molarity.

Molarity (M) = 0.43 mol NaCl solute / 0.250 L solution = 1.7 M NaCl (original solution)

2. Solve for the molarity of the final (diluted) solution.

Remember that the amount of solute remains constant in a dilution problem; it is just the total volume of the solution that changes due to the addition of solvent.

Molarity (M) = 0.43 mol NaCl solute / 1.2 L solution

Molarity (M) of the final solution = 0.36 M NaCl

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2 years ago