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IgorC [24]
3 years ago
10

Help plz ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry
1 answer:
ddd [48]3 years ago
7 0
Honestly I don’t even know
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What are the major parts of the ecosystem
eduard

Answer:

Ecosystems have lots of different living organisms that interact with each other. The living organisms in an ecosystem can be divided into three categories: producers, consumers and decomposers. They are all important parts of an ecosystem. Producers are the green plants.

Explanation:

Hope this helps

4 0
3 years ago
HELP PLS EXPLAIN!
Step2247 [10]

Answer:

Space exploration thus supports innovation and economic prosperity by stimulating advances in science and technology, as well as motivating the global scientific and technological workforce, thus enlarging the sphere of human economic activity.

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2 years ago
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What is the volume of 0.200 mol of an ideal gas at 200. kPa and 400. K?
gregori [183]

The ideal gas under STP is 22.4 L/mol. While the gas has a rule of P1V1/T1=P2V2/T2. So the volume under 101 kPa and 273 K is 0.2*22.4=4.48 L.


7 0
3 years ago
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A 1.50 L buffer solution is 0.250 M in HF and 0.250 M in NaF. Calculate the pH of the solution after the addition of 0.100 moles
alexgriva [62]

Answer : The pH of the solution is, 3.41

Explanation :

First we have to calculate the moles of HF.

\text{Moles of HF}=\text{Concentration of HF}\times \text{Volume of solution}

\text{Moles of HF}=0.250M\times 1.50L=0.375mol

Now we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.8\times 10^{-4})

pK_a=4-\log (6.8)

pK_a=3.17

The reaction will be:

                             HF+OH^-\rightleftharpoons F^-+H_2O

Initial moles     0.375     0.100   0.375

At eqm.   (0.375-0.100)      0     (0.375+0.100)

                     = 0.275                    = 0.475

Now we have to calculate the pH of solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[F^-]}{[HF]}

Now put all the given values in this expression, we get:

pH=3.17+\log [\frac{(\frac{0.475}{1.50})}{(\frac{0.275}{1.50})}]

pH=3.41

Thus, the pH of the solution is, 3.41

8 0
3 years ago
108/49 In ? 108/48 Cd + ? In the equation above, what particle or type of radiation needs to be included on the right hand side
Oksanka [162]

Answer: b) positron

Explanation:

The antiparticle or the antimatter counterpart of the electron is called positron.

The positron has an electric charge of +1 e and same mass as an electron. When a positron collides with an electron, annihilation takes place.

Below is an attachnent that further explains this

7 0
2 years ago
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