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9966 [12]
4 years ago
5

Is everything that we can see in the universe matter

Chemistry
2 answers:
Drupady [299]4 years ago
8 0

Answer:

no

Explanation:

gayaneshka [121]4 years ago
6 0
I think that everything in the universe matters
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What is the percent by mass of oxygen in carbon dioxide (CO2)?
wariber [46]

Answer:

= 72.73%

Explanation:

The percentage by mass of an element is given by;

% element = total mass of element in compounds/molar mass of compound × 100

The mass of oxygen in carbon dioxide = 32 g

Molar mass of CO2 = 44 g

Therefore;

% of O2 = 32/44 × 100%

             <u>= 72.73%</u>

8 0
3 years ago
Which of the following statements about the greenhouse effect is false?
Nataly_w [17]
The answer is a ik for a fact
3 0
3 years ago
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A mixture contains O2 at 700. torr pressure, F2 at 500. torr pressure, and Cl2 at 500. torr pressure. What is the total pressure
Softa [21]

You have to use Dalton's law of partial pressure for this question. Dalton's law of partial pressure basically states that the total pressure of the system is all of the partial pressures of the components added together. Therefore to answer the question you just need to add all the patial pressures together meaning that the total pressure would be 700+500+500=1700.

The answer would be 1700 torr.

I hope this helps. Let me know if anything is unclear or if you have any further questions.

3 0
4 years ago
Antimony has two naturally occuring isotopes, 121 Sb and 123 Sb . 121 Sb has an atomic mass of 120.9038 u , and 123 Sb has an at
valina [46]

Answer:

Percentage abundance of 121 Sb is = 57.2 %

Percentage abundance of 123 Sb is = 42.8 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, 121 Sb :

% = x %

Mass = 120.9038 u

For second isotope, 123 Sb:

% = 100  - x  

Mass = 122.9042 u

Given, Average Mass = 121.7601 u

Thus,  

121.7601=\frac{x}{100}\times 120.9038+\frac{100-x}{100}\times 122.9042

120.9038x+122.9042\left(100-x\right)=12176.01

Solving for x, we get that:

x = 57.2 %

<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>

<u>percentage abundance of 123 Sb is = 100 - 57.2 %  = 42.8 %</u>

6 0
3 years ago
What are some common examples of solids, liquids and gas?
Sonja [21]
Solids- wood, sand, brick, rock

Liquids- water, milk, blood, coffee

Gases- air, helium, nitrogen, hydrogen
3 0
3 years ago
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