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alexgriva [62]
2 years ago
11

A candle is placed between a concave mirror and its focal point.

Chemistry
2 answers:
natali 33 [55]2 years ago
6 0

Virtual and enlarged..............

What grade are you in btw ?

jarptica [38.1K]2 years ago
3 0

Answer: C AND D

Explanation:

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Which group on the periodic table is a noble gas most likely to bond with?
TiliK225 [7]

Answer:

The noble gases are the chemical elements in group 18 of the periodic table. They are the most stable due to having the maximum number of valence electrons their outer shell can hold. Therefore, they rarely react with other elements since they are already stable.Explanation:

3 0
3 years ago
A titanium cube contains 2.86×1023 atoms. What is the edge length l of the cube? The density of titanium is 4.50 g/cm3 . (The v
elena55 [62]

Answer:

I = 1.716 cm

Explanation:

We want the length of the cube. In this case, we know that the volume of a cube is:

V = I³

From here we can solve for I:

I = ∛V  (1)

Now, the volume can be obtained using data of density. The expression for density is:

d = m/V

Solvinf for V:

V = m/d (2)

The mass of the cube, can be obtained with the moles and molar mass of titanium:

m = n * MM (3)

And finally, the moles (n) can be obtained using avogadro number:

1 mol ----> 6.02x10²³ atoms (4)

Therefore, to get the length we need to calculate with the atoms of titanium, the moles, then mass, volume and finally the length. Let's calculate the moles of titanium using the ratio of (4):

nTi = 2.86x10²³ / 6.02x10²³ = 0.475 moles

Now, let's calculate the mass using (3) and the molecular mass of titanium which is 47.867 g/mol:

m = 0.475 * 47.867 = 22.737 g

Let's replace this value in (2) to get the volume:

V = 22.737 / 4.5 = 5.053 cm³

Finally, the length using (1):

I = ∛5.053

I = 1.716 cm

This is the length of the cube

4 0
3 years ago
Please help ASAP! Will mark brainliest.
Maslowich

Answer:C. Compounds are the smallest unit of an element that occur on the periodic table!!

Explanation:

3 0
4 years ago
Read 2 more answers
How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
Pure substances contain only one type of a. Atoms only. B. Molecules only. C. Atoms or molecules. D. Mixture.
Nesterboy [21]
A. Atoms only. An element cannot be separated into simpler materials
3 0
3 years ago
Read 2 more answers
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