Answer:
4121 years
Explanation:
From;
0.693/t1/2 = 2.303/t log No/N
t1/2= half life of the carbon-14
No= count rate of the living tissue
N= count rate of the sample
t = age of the sample
0.693/5730 =2.303/t log (13.5/8.2)
1.21 * 10^-4 = 2.303/t * 0.2165
1.21 * 10^-4 = 0.4986/t
t = 0.4986/1.21 * 10^-4
t = 4121 years
Answer:
wouldn't it be the #2 because +∆H um I forgot
The given above pretty much states already that with the presence of the calcium carbonate which acts as the buffer will allow the solution to withstand changes in acidity. The greater the amount, the higher chances that it will be able to withstand the said changes. Therefore, if Lake X had greater ppm of CaCO3 then, it will be able to withstand greater amount of acid rain.
First, we need the no.of moles of O2 = mass/molar mass of O2
= 55 g / 32 g/mol
= 1.72 mol
from the balanced equation of the reaction:
2H2 (g) + O2(g) → 2H2O(g)
we can see that the molar ratio between O2: H2O = 1: 2
So we can get the no.of moles of H2O = 2 * moles of O2
= 2 * 1.72 mol
= 3.44 mol
So by substitution by this value in ideal gas formula:
PV = nRT
when P = 12.4 atm & n H2O = 3.44 mol & R= 0.0821 & T = 85 + 273=358K
12.4 atm *V = 3.44 * 0.0821 * 358 = 8.15 L
∴ V ≈ 8.2 L
Answer:
Iron (II) nitrate is ionic compound
Explanation:
Formula:
Fe(NO₃)₂
Iron (II) nitrate is ionic compound.
Its molecular mass is 179.85 g/mol.
NO⁻₃ is anion while Fe⁺² is cation.
Iron loses its two electron which is accepted by nitrate.
Its molecular formula can be written as FeN₂O₆.
Its color is pale green.
Its melting point is 333.65 K.
It is para magnetic compound.
it is mostly present in non hydrated form.
It is also known as ferric nitrate.
It is used to form sodium amide.
Its is also used catalyst.
