Given that an animal shelter houses three kinds of animals: dogs, cats and rabbits and it has a total of 126 animals. 1/3 of the animals are cats. This means, 1/3 of 126 is 42. So there are 42 cats. 3/4 of the remaining animals, which is 84 are dogs. So 3/4 of 84 is 63. So there are 63 dogs. 63 dogs plus 42 cats is 105 animals. 126 minus 105 is 21. Therefore, there are only 21 rabbits. Hope this helps.
Answer:
33600 m²
Step-by-step explanation:
The top and bottom horizontal sides are parallel, so this is a trapezoid with bases DC and AB. The height is BC.
area of trapezoid = (a + b)h/2
where a and b are the lengths of the bases, and h is the height.
We need to find the height, BC.
Drop a perpendicular from point A to segment DC. Call the point of intersection E. E is a point on segment DC.
DE + EC = DC
EC = AB = 360 m
DC = 600 m
DE + 360 m = 600 m
DE = 240 m
Use right triangle ADE to find AE. Then BC = AE.
DE² + AE² = AD²
DE² + 240² = 250²
DE² = 62500 - 57600
DE² = 4900
DE = √4900
DE = 70
BC = 70 = h
area = (a + b)h/2
area = (600 m + 360 m)(70 m)/2
area = 33600 m²
3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5
f = 2
Simplify both sides of the equation <span><span>1.25f</span>+2</span>=<span><span>−<span>2.75f</span></span>+<span>10
Add 2.75 to each side </span></span><span><span>4f</span>+2</span>=<span>10
Subtract 2 from both sides </span><span>4f</span>=<span>8
Divide each side by 4 </span>f=<span>2</span>
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