Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
<h3>
Answer: D. Kira used published data that is quantitative.</h3>
The published data refers to the government census info being published online. She did not do an observational study because she didn't go to each household herself (rather let the census workers do that task).
The data is quantitative because she is looking at the number of people living in homes in her city. Quantitative data is simply dealing with quantities or numbers. Contrast this with qualitative data that talks about something like color choice.
Answer:
2
Step-by-step explanation:
The answer would be 2 because it reduces to the same system of equations as the original, which I knew since the first equation was the same and if you divide everything in the second by 2, you'll get 3x-y=8. :)
<h3>Given</h3>
new balance = previous balance + finance charge + purchases - payments
previous balance = $34.80
finance charge = $0.75
purchases = $83.21
payments = $5.50
<h3>Find</h3>
new balance
<h3>Solution</h3>
Fill in the given information and do the arithmetic.
... new balance = previous balance + finance charge + purchases - payments
... new balance = $34.80 + 0.75 + 83.21 - 5.50
... new balance = $113.26 . . . . matches the 2nd choice
Given that the number is x,
10% increase will give us a new number of:
110/100*x
=1.1x
10% decrease will give us a new number of:
90/100*1.1x
=0.99x
This implies the new number is less than the original number
