2x - 3(x-1) = -1
2x -3x + 3 = -1
-1x + 3 = -1
-1x = -4
x = 4
y = 4 - 1
y = 3
These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
PEMDAS Solve the parentheses first so 9+4=13. Then do the division so 6/6=1. Now the equation is 37- 13+ 1. Then work left to right. 37-13= 24 then 24+1=25.
The y-intercept is basically the value of the output of the function, g(x), when x=0.
Let's replace g(x) with the variable y to make this look a bit simpler.
2y + 3x = 6
Now, we enter the value of x=0 to get the y-intercept.
2y + 0 = 6
2y = 6
Divide both sides by 2
y = 3
The value of y is 3. Now enter the values of x=0 and y=3 into point-form (x,y) to get (0,3). You should know which answer choice to choose now.
Have an awesome day!
