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3 years ago

Solve -25 = -3x + 24x - 2 = 183- 6x + 5 + 10x - 1

Mathematics

2 answers:

AlekseyPX3 years ago

7 0

Answer:

Ok, so if the top line (-25 = -3x + 2) is separate and the second line is separate (4x - 2 = 18) then the answer is x = 9 and x = 5

Step-by-step explanation:

Can you please elaborate on what the equations are? I will still answer the question.

lord [1]3 years ago

7 0

Answer: x=1+2/21

Step-by-step explanation:

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5 x + 4y= 16 X+y = 3.5 Find out what each letter is equal to X= Y=

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X=4
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4 years ago

What is 37 and 1/2 simplified?

yarga [219]

37 and 1/2 could mean:
37+ (1/2)
37 times 1/2

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4 years ago

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Ghella [55]

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3 years ago

Read 2 more answers

Rectangle QRST has vertices located at Q(-9, -3), R(-1,-1), S(0,-5) and T(-8, -7). What is the length of side ST?

yaroslaw [1]

Answer:

$\huge\boxed{\sf |ST| = 8.2 \ units}$

Step-by-step explanation:

S = (x1,y1) = (0,-5)

T = (x2,y2) = (-8,-7)

Using distance formula to find the length of ST.

$|ST|= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\\|ST| = \sqrt{(-8-0)^2+(-7-(-5))^2} \\\\|ST| = \sqrt{(-8)^2+(-7+5)^2} \\\\|ST| = \sqrt{64+(2)^2}\\\\|ST| = \sqrt{64+4} \\\\|ST| = \sqrt{68} \\\\|ST| = 8.2 \ units\\\\\rule[225]{225}{2}$

8 0

3 years ago

You are trying to determine if you should accept a shipment of eggs for a local grocery store. About 4% of all cartons which are

padilas [110]

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion $\hat p =\dfrac{x}{n}$

= 16/300

= 0.0533

∴

$P(\hat p \leq 0.0533) = P\bigg ( \dfrac{\hat p - p}{\sqrt{\dfrac{P(1-P)}{n}}}\leq\dfrac{0.0533 - 0.04}{\sqrt{\dfrac{0.04(1-0.04)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.04(0.96)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.0384}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{1.28 \times 10^{-4}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{0.0113}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )$

From the z tables;

= 0.8809

Let X be the random variation that follows a normal distribution;

Then;

population mean $\mu$ = n × p

population mean $\mu$ = 300 × 0.04

population mean $\mu$ = 12

The standard deviation $\sigma = \sqrt{np(1-p)}$

The standard deviation $\sigma = \sqrt{300 \times 0.04(1-0.04)}$

The standard deviation $\sigma = \sqrt{11.52}$

The standard deviation $\sigma = 3.39$

The z -score can be computed as:

$z = \dfrac{x - \mu}{\sigma}$

$z = \dfrac{16 -12}{3.39}$

$z = \dfrac{4}{3.39}$

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z ≤ 1.18)

= 0.8809

5 0

3 years ago

Solve -25 = -3x + 24x - 2 = 183- 6x + 5 + 10x - 1​

Solve -25 = -3x + 24x - 2 = 183- 6x + 5 + 10x - 1