The answer I'm pretty sure is a because it can't be d because ionic binding the electrons are affected and it can't be c because that's covalent bonding and it can't be b because they don't swap electrons.
The term which is used is homogeneous.
when sugar is completely dissolved in the water, the mixture or solution homogeneous, both in same phase and same uniform texture that is liquid.
There two types of mixtures are heterogeneous and homogeneous in different phases.
If sugar is not completely dissolved in water and you see the crystals of sugar in water, then the solution will be heterogeneous.
Answer : -19.6
Explanation : We can calculate this using the combine equation of boiling point and depression in freezing point and obtain a combined equation which is
∆T(f) = ∆T(b) x {K(f) / K(b)} ;
Where ∆T(f) is depression in freezing point,
∆T(b) is elevation in boiling point,
K(f) is cryoscopic constant for water it is 1.86
K(b) is ebullioscopic constant for water it is 0.512
So we can solve the equation,
∆T(f) = (105.4 -100) X
= 19.6
So when we have the freezing point depression as 19.6,
we know water freezes at 0° C so the freezing point will be 0 - 19.6 = -19.6 °C