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PtichkaEL [24]
3 years ago
13

How do I find lattice energy with the overall heat of dissolution of aluminum sulfate?

Chemistry
1 answer:
NeTakaya3 years ago
3 0

Explanation:

you can use Born-Lande equation,

U=-(A×e^2×Z+ ×Z- ×N)\r ×(1-1/n)

here,U=lattice energy

A=madelung constant

n=Born exponent(depends on repulsion between ion)

e=charge of electron

Z+,Z-=charge of cation and anion

r=distance between cation and its neighbour anion in

space lattice

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What is one way scientists can split a substance into its simpler components
notsponge [240]

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Explanation:

Electrolysis is a chemical change produced by sending an electric current through a compound. Electrolysis works because the hydrogen and oxygen ions are held together by an electric attraction.

5 0
3 years ago
Why is salad dressing a solution?
umka21 [38]

Explanation:

A prime illustration of sour salad dressing formulas and suspension. Vinegar is also an acetic acid product which is dispersed in water, so we can't even see molecules in the oil. The removal throughout the liquid phase to make a solution.

5 0
2 years ago
What is the molarity of 20.2 g of potassium nitrate, KNO3, in enough water to make 250.0 mL of solution
KATRIN_1 [288]

Answer:

0.8M

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8 0
3 years ago
Oxygen has an atomic number of 8. in order to fill its outer electron shell, how many electrons does it need?
Lina20 [59]
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3 0
3 years ago
A solution of 2-propanol and 1-octanol behaves ideally. Calculate the chemical potential of 2-propanol in solution relative to t
andrew-mc [135]

Answer:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

Explanation:

The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:

\mu (l) = \mu ^{\circ} (l) + R*T*ln(x)

<u>Where:</u>

<em>μ (l): is the chemical potential of 2-propanol in solution    </em>

<em>μ° (l): is the chemical potential of pure 2-propanol   </em>

<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>

<em>T: is the temperature = 82.3 °C = 355.3 K </em>

<em>x: is the mole fraction of 2-propanol = 0.41 </em>

\mu (l) = \mu ^{\circ} (l) + 8.314 \frac{J}{K*mol}*355.3 K*ln(0.41)

\mu (l) = \mu ^{\circ} (l) - 2.63 \cdot 10^{3} J*mol^{-1}

\mu (l) - \mu ^{\circ} (l) = - 2.63 \cdot 10^{3} J*mol^{-1}  

Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.    

I hope it helps you!    

8 0
4 years ago
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