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PtichkaEL [24]
3 years ago
13

How do I find lattice energy with the overall heat of dissolution of aluminum sulfate?

Chemistry
1 answer:
NeTakaya3 years ago
3 0

Explanation:

you can use Born-Lande equation,

U=-(A×e^2×Z+ ×Z- ×N)\r ×(1-1/n)

here,U=lattice energy

A=madelung constant

n=Born exponent(depends on repulsion between ion)

e=charge of electron

Z+,Z-=charge of cation and anion

r=distance between cation and its neighbour anion in

space lattice

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Nat2105 [25]

A good reason for a desert fox to show this pattern of behavior because hunting at night allows the fox to use its night vision.

<h3>What is Hunting?</h3>

Thi9s is commonly practised by predators such as fox in which they capture and kill other animals for food.

The fox has a good night vision which makes it able to hunt for animals during the night also. This is why option C is chosen as the most appropriate choice.

Read more about Hunting here  brainly.com/question/81175

6 0
2 years ago
During a long drought, many deer become weak because a basic need is not being met. What requirements for life are the deer most
saw5 [17]

Enough water, I actually took this test! <3

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3 0
3 years ago
Read 2 more answers
Sheena has a lump of sodium, a lump of potassium and a lump of lithium, but they’ve got mixed up and she doesn’t know which one
Arada [10]

Answer:

Explanation:

Just saw your request regarding answering this so here it is:

All of them belong of Group 1 in periodic table and thus are highly reactive! Pattern of reactivity for Group 1 (Alkali metals) increases as you move down the group as their radius keeps increasing and thus electrons can be easily lost. Thus, to ID the lumps, Sheena should look at their reactivity and she should get the following trend:

Most reactive: Potassium (K)

Intermediate: Sodium (Na)

Least reactive: Lithium (Li)

Hope it helps!

5 0
3 years ago
Which statement best describes how sediment forms?
Anit [1.1K]

Weathering breaks down rock and other material

8 0
2 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

<u>Vi = 0.145 l or 145 ml</u>

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
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