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zlopas [31]
3 years ago
9

The arched interior is comprised of a semi circle and a rectangle the diameter of the semi circle is 24 inches the length of the

rectangle is 36 inches what is the area of the arch interior
Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

1090sqr.inches

Step-by-step explanation:

The area of the arched-interior can be calculated by adding the value of the area of the semi circle to that of the rectangle.

The semi-circle has a diameter of 24 inches while the rectangle has a length of 36 inches.

The area of the semi circle is simply: πr^2/2

Since r = d/2, r here is 24/2 = 12

Area of semicircle is thus 22/7 * 12 * 12 * 1/2 = 226.2sqr.inches

The rectangle measures 24 inches by 36 inches. The area here is 24 * 36 = 864 sqr.inches

The total area is thus; 864 + 226.2 = 1090 sqr.inches

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\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{30K_M}{K_M + 30K_M}\\\dfrac{v}{V_{max}}=\dfrac{30}{1 + 30}\\\dfrac{v}{V_{max}}=\dfrac{30}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{30}{31}X100=96.77\%

(b)When K_M=30[S]

\dfrac{v}{V_{max}}=\dfrac{[S]}{K_M + [S]}\\\dfrac{v}{V_{max}}=\dfrac{[S]}{30[S] + [S]}\\\\=\dfrac{1[S]}{30[S] + 1[S]}\\=\dfrac{1}{30 + 1}\\\dfrac{v}{V_{max}}=\dfrac{1}{31}\\$Expressed as a percentage\\\dfrac{v}{V_{max}}=\dfrac{1}{31}X100=3.23\%

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