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Dafna11 [192]
3 years ago
15

If 4 (x-2/3) = -18, what is the value of 2x

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

-11.5

Step-by-step explanation:

4(x-2/3)=-18

4x-8/3=-18

4x-8=-18×3

4x-8=-54

4x=-54+8

4x=-46

x=-46/4

x=-11.5

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en un maratòn participan corredores de todos los continentes 5/6 de los corredores son europeos se sabe que los americanos son l
Marysya12 [62]

Usando proporciones, se encuentra que 400 africanos han participado.

En total, hay x participantes.

\frac{5}{6} de los corredores son europeos, o sea:

E = \frac{5x}{6}

Los americanos son la dècime parte de los europeos, o sea:

Am = \frac{1}{10}E = \frac{5x}{60} = \frac{x}{12}

Los africanos son la quinta parte de los americanos, o sea:

Afr = \frac{1}{5}Am = \frac{x}{60}

En la carrera han inscritos 24 000 participantes, o sea, x = 24000. Por eso, la cantidad de africanos es:

Afr = \frac{x}{60} = \frac{24000}{60} = 400

Para obtener más información sobre las proporciones, puedes visitar a brainly.com/question/24615636

8 0
2 years ago
(#5) A carpenter has two different-sized circular saws. The smaller saw has the radius shown. I couldn't show it, so it is 1.25
grin007 [14]

Answer:

4.71 in. difference

Step-by-step explanation:

so, the radius of the smaller saw is 1.25 and the diameter is double the radius. so it is 2.5 in diameter. the larger saw is 1.5 in greater which is 4 in.

to find circumference, you have to use the solution C = πd or circumference = pi x diameter.

3.14 x 2.5 = 7.85

4 x 3.14 = 12.56

subtract 7.85 from 12.56 to get your answer! i hope this helps!

5 0
2 years ago
What is a necessary step for constructing perpendicular lines through a point off the line?
Nostrana [21]

Answer:

Find another point on the perpendicular line.

Step-by-step explanation:

Given an original line "m", and a point off the line "Q", in order to construct a second line "p", meant to be perpendicular to "m" through the point "Q", fundamentally, the only truly necessary step to construct a perpendicular line through is to find another point on the yet-to-be-found perpendicular line.

Most often, this is accomplished by exploiting the fact that "p" is the set of all points that are equidistant from any pair of points that are symmetric about "p".

Since the symmetry must be about "p", and we don't even know where "p" is, one often finds two points on "m" that are equidistant from "Q".

This can be accomplished by adjusting a compass to a fixed radius (larger than the distance from "Q" to "m"), and making an arc that intersects "m" in two places.  Those two places will be equidistant from "Q", and are simultaneously on line "m".  Thus, these two points, "A" & "B" are symmetric about "p".

Since "A" & "B" are symmetric about "p", they are equidistant from "p", and are on "m".  One could try to find the point of intersection between "p" and "m" through construction, but this is unnecessary.  We need only find a second point (besides "Q") that is equidistant from "A" & "B", which will necessarily be a point on "p", to form the line perpendicular to "m".

To do this, fix the compass with any radius, and from "A" make a large arc generally in the direction of "B", and make the same radius arc from "B" in the direction of "A" such that the two arcs intersect at some point that isn't "Q".  This point of intersection we can call point "T", and the line QT is line "p", the line perpendicular to the original line, necessarily containing "Q".

8 0
2 years ago
What does this mean?<br> ~p~9
Montano1993 [528]
~p~9 .............
Show work
9=p
6 0
3 years ago
What is 5s fact to multiply 6x8?
arlik [135]
What are you trying to ask ??
4 0
3 years ago
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